Re: binary conversion

Hi

Whoops! Sorry about that, it should have been AND with 0xff
and not 0x00, it was early!!

byte num[4] = // whatever

int bigE =   ((num[0] & 0xff)
       | ((num[1] & 0xff) << 8)
       | ((num[2] & 0xff) << 16)
       | ((num[3] & 0xff) << 24));


Or this, whatever big endian is ... try em both

int bigE =  ((num[3] & 0xff)
       | ((num[2] & 0xff) << 8)
       | ((num[1] & 0xff) << 16)
       | ((num[0] & 0xff) << 24));


This definetly works for 8-bit binary data
represented as an array of 4 for a 32-bit int.

Niall

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