Re: binary conversion

thank you Erling,

your's way and Niall's way, both work

thank you very much..

Ken

--- Erling Egholm <[email protected]> wrote:
> Try this ...
>
>     int num [] = new int[4];
>
>     num[0] = Integer.parseInt("00000000", 2);
>     num[1] = Integer.parseInt("00001110", 2);
>     num[2] = Integer.parseInt("00110101", 2);
>     num[3] = Integer.parseInt("10000001", 2);
>
>     int bigE = ((num[3]) | ((num[2]) << 8) |
> ((num[1]) << 16) | ((num[0]) << 24));
>
>     System.out.println("bigE = " + bigE);
>
>     // Output: bigE = 931201
>
> Erling
>
> ----- Original Message -----
> From: "K D" <[email protected]>
> To: <[email protected]>
> Sent: Friday, May 23, 2003 7:38 PM
> Subject: Re: binary conversion
>
>
> > Hi,
> >
> > I tried your method, and I got "0" for both way
> > I am not sure why,
> > but here is my input
> >
> > 00000000
> > 00001110
> > 00110101
> > 10000001
> >
> > these number = 931201 (year,month,day)
> >
> > thanks
> >
> >
> > --- Niall Gallagher <[email protected]> wrote:
> > > >In the example that you gave it,
> > > >you are converting an integer
> > > >into big and small endian right?
> > > >
> > > >I guess what I tried to ask was
> > > >I have a 4 byte of data,
> > > >and it is not stored in ascci format
> > > >but rather in byte data only, so I have
> > > >to read in data as byte array like this...
> > > >
> > > >byte num [] = new byte[4]
> > >
> > >
> > > Hi
> > >
> > > What you have is a list of 8-bit bytes and what
> you
> > > want to do
> > > is to convert these into a single integer. So
> for
> > > example if
> > > the integer was 1 you have the equivelant of
> > >
> > > a [0000 0001]
> > > b [0000 0000]
> > > c [0000 0000]
> > > d [0000 0000]
> > >
> > > Where a is num[0] and d is num[3]. Well if I
> > > remember big
> > > endian right what you want is the binary 32-bit
> > > integer
> > >
> > >  [0000 0000 0000 0000 0000 0000 0000 0001]
> > >
> > > So to do this the following expression should
> work.
> > >
> > > int bigE =   ((num[0] & 0x00)
> > >        | ((num[1] & 0x00) << 8)
> > >        | ((num[2] & 0x00) << 16)
> > >        | ((num[3] & 0x00) << 24));
> > >
> > > This should give you the correct integer value,
> > > However
> > > I may have my big and little endian upside down,
> in
> > > which
> > > case the following sould work
> > >
> > > int bigE =  ((num[3] & 0x00)
> > >        | ((num[2] & 0x00) << 8)
> > >        | ((num[1] & 0x00) << 16)
> > >        | ((num[0] & 0x00) << 24));
> > >
> > >
> > > I have had to do this many times before, so you
> > > should
> > > have no problem with these expressions, if you
> do,
> > > let me know.
> > >
> > > Niall
> > >
> > >
> >
>
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