Re: RequestDispatcher forward and include methods

This always causes confusion.  Here's one way to illustrate this: except
for schemes involving exceptions, there is no way for a "called" method
to cause the code in the "calling" method to skip the rest of the
method.  In short, calling the "forward()" method may transfer
"control", but it's only logical control over what servlet is supposed
to be generating output to the client.  It has nothing to do with
controlling execution of code in methods.  So, even though the call to
"forward()" will have generated output from the "called" servlet, as
soon as it returns from the "forward()" call, if there's further code in
the calling method, it will be executed.

> -----Original Message-----
> From: Hiren Dossani [mailto:[email protected]]
>
> afaik, forward method of RequestDispatcher transfers control to the
> forwarded servlet. means one can never come back to the fowarding
servlet.
> however, i don't get why the last statement in the following
forwarding
> servlet was executed after using RequestDispatcher's  forward method.
>
> forwarding servlet code:
> -------------------------
>
> out.println("<font color=\"ff0000\"><h2>This text is from
> TallyPage1</font>\n<br><p>");
>       RequestDispatcher r =
> getServletContext().getNamedDispatcher("Tally");
>      r.forward(req, resp);
>  out.println("<font color=\"ff0000\"><h4>This line is after forward
> method</font>\n<br><p>");
>
>
> forwarded servlet code:
> ----------------------
> out.println("in forwarded servlet");
>
> i shouln't see the last line in forwarding serlvet being displayed on
the
> browser.

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