Re: Conditional problem

Hi Programozás,

what you are doing in the second case is correct. You access the page 
components via the Page components property. This returns a map, so to 
access the actual component you specify its name, then you access the 
property of the components.

page.components.[component name].[property name]

See IPage implements IComponent which has a getComponents() method.

Regards Malcolm

>From: Programozás <[email protected]>
>To: "Tapestry Developer" <[email protected]>
>Subject: [Tapestry-developer] Conditional problem
>Date: Sun, 17 Nov 2002 23:26:26 +0100
>
>Hello!
>
>I have a page with a component in it. The page has a persistent property 
>'openedFolderId' which I would like to use in the component definition. The 
>component has a property named 'folder'.
>If I write in the component definition:
>
>     <component id="ifFolderOpened" type="Conditional">
>         <binding name="condition" expression="page.openedFolderId == 
>folder.id"/>
>     </component>
>
>then I get an exception:
>
>           ognl.NoSuchPropertyException
>           folder
>
>
>BUT if I write:
>
>     <component id="ifFolderOpened" type="Conditional">
>         <binding name="condition" expression="page.openedFolderId == 
>page.components.categories.folder.id"/>
>     </component>
>
>where 'categories' is the name of my component in the page definition then 
>it works!
>
>Help me, what am I doing wrong?
>Thanks,
>Norbi


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