RE: RE: RE: Combo Chart with Trendline

Friedli Beat <[email protected]> Tue, 10 Aug 2004 08:45:47 +0200
Newsgroups gmane.comp.krysalis.jcharts.devel
Message-ID <[email protected]>
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I absolutely agree. If somone wants to draw a regression line he must know
what the relation of the data points (in a scatterplot) is. The relation
migth be linear, quadratic, qubic or whatever. See
http://www.tufts.edu/~gdallal/straight.htm
<http://www.tufts.edu/~gdallal/straight.htm> . For my purpose (and probably
for 80% of the others) it would be absolutely enogh to have a linear
regression.
 
Beat
 
 
>Well the non-linear regression line is a pretty complicated do-hickey.  So,
> making it an option sounds good on paper, but unless someone finds an
> algorithm that is more than a calculus proof, I"m not going to be able to
> build it.  
>  
> Your second point is good, but I don"t think anything is particularly
> special about a regression line that makes it any different than any other
> chart.  So having n of them shouldn"t be a big deal. 
> err, it"ll be a big deal now, because the proof of concept I uploaded,
> doesn"t allow it.  But I"m sure some smart people can fix "er up.
>  
> Nathan

 

 <http://www.tufts.edu/~gdallal/straight.htm>  


 


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<DIV><FONT face=Arial><FONT size=2><SPAN class=620443406-10082004>I absolutely 
agree. If somone wants to draw a regression line he must know what the relation 
of the data points (in a scatterplot) is. The relation migth be linear, 
quadratic, qubic or whatever.&nbsp;See </SPAN><SPAN class=620443406-10082004><A 
href="http://www.tufts.edu/~gdallal/straight.htm">http://www.tufts.edu/~gdallal/straight.htm</A>. 
For my purpose (and probably for 80% of the others) it would be absolutely enogh 
to have a linear regression.</SPAN></FONT></FONT></DIV>
<DIV><SPAN class=620443406-10082004><FONT face=Arial 
size=2></FONT></SPAN>&nbsp;</DIV>
<DIV><SPAN class=620443406-10082004>Beat</SPAN><SPAN 
class=620443406-10082004><FONT face=Arial size=2></FONT></SPAN></DIV>
<DIV><SPAN class=620443406-10082004><FONT face=Arial 
size=2></FONT></SPAN>&nbsp;</DIV>
<DIV><SPAN class=620443406-10082004><FONT face=Arial 
size=2></FONT></SPAN>&nbsp;</DIV>
<DIV><SPAN class=620443406-10082004>&gt;</SPAN>Well the non-linear regression 
line is a pretty complicated do-hickey.&nbsp; So,<BR><SPAN 
class=620443406-10082004>&gt;</SPAN>&nbsp;making it an option sounds good on 
paper, but unless someone finds an<BR><SPAN 
class=620443406-10082004>&gt;</SPAN>&nbsp;algorithm that is more than a calculus 
proof, I"m not going to be able to<BR><SPAN 
class=620443406-10082004>&gt;</SPAN>&nbsp;build it.&nbsp;&nbsp;<BR><SPAN 
class=620443406-10082004><FONT face=Arial 
size=2>&gt;</FONT></SPAN>&nbsp;&nbsp;<BR><SPAN 
class=620443406-10082004>&gt;</SPAN> Your second point is good, but I don"t 
think anything is particularly<BR><SPAN 
class=620443406-10082004>&gt;</SPAN>&nbsp;special about a regression line that 
makes it any different than any other<BR><SPAN 
class=620443406-10082004>&gt;</SPAN>&nbsp;chart.&nbsp; So having n of them 
shouldn"t be a big deal.&nbsp;<BR><SPAN class=620443406-10082004>&gt;</SPAN> 
err, it"ll be a big deal now, because the proof of concept I uploaded,<BR><SPAN 
class=620443406-10082004>&gt;</SPAN>&nbsp;doesn"t allow it.&nbsp; But I"m sure 
some smart people can fix "er up.<BR><SPAN class=620443406-10082004><FONT 
face=Arial size=2>&gt;</FONT></SPAN>&nbsp;&nbsp;<BR><SPAN 
class=620443406-10082004>&gt;</SPAN> Nathan<BR></DIV>
<DIV><FONT face=Arial size=2></FONT>&nbsp;</DIV>
<P><FONT face=Arial size=2><A 
href="http://www.tufts.edu/~gdallal/straight.htm"></A></FONT>&nbsp;</P>
<P><FONT face=Arial size=2></FONT><BR>&nbsp;</P>
<P>
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