Re: Converting packed decimal to a char array

On 2015-01-10 05:56, Jevgeni Astanovski wrote:
>...
> It produces the following:
> After conversion A: !          125678!
> What I expected is a number padded with zeros in the left.
> I have to check if the receiver program will accept the changed input...
>

Is the result correct except for the leading zeros? You could loop 
through the result and replace the leading blanks with zeros. If you 
find a sign, you'd have to move it to the beginning of the string.

Something like this:

    for (i = 0; i < RcvLen; i++)
    {
       switch (szOutput[i])
       {
       case '-':
          szOutput[i] = '0';
          szOutput[0] = '-';
          return;
       case ' ':
          szOutput[i] = '0';
          break;
       default:
          return;
       }
    }

-- 
Barbara

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