Re: C++0x syntax question

Kelly,

Did this code ever  compile on IBM i under previous versions of the IBM 
ILE C++ compiler?

IBM does not strictly follow the ANSI standards for either C or C++ ...

You could also install the open-source GCC compiler and it would 
probably compile this code for you ... of course, the resulting object 
code would run under PASE ...

Mark

 > On 9/12/2017 10:57 AM, Kelly Beard wrote:
> I am attempting to compile the following code under the newer compiler
> under V7R3 and the LANGLVL *EXTENDED0X option enabled.  I am using the
> 5799PTL 'icc' compiler front-end to do this.  The command default for
> CRTCPPMOD has been altered to always have *EXTENDED0X on by default.  I am
> getting this:
>
> "testme.cpp", line 14.18: CZP0130 (30) "start" is not declared.
>
> The offending line looks like:
>
> T::size_type start = 0;
>
> So, is there a change to the C++11 syntax here?  Thanks in advance, as
> always.  Here is the test program.
>
> #include <iostream>
> #include <string>
> #include <sstream>
> #include <iomanip>
> #include <vector>
> #include <unistd.h>
>
> using namespace std;
>
>
> template<typename T> vector<T> split(const T & str, const T & delimiters)
> {
>      vector<T> v;
>      T::size_type start = 0;
>      size_t pos = str.find_first_of(delimiters, start);
>      while (pos != T::npos) {
>          if (pos != start) { // ignore empty tokens
>              v.push_back(str.substr(start, pos - start));
>          }
>          start = pos + 1;
>          pos = str.find_first_of(delimiters, start);
>      }
>      if (start < str.length()) { // ignore trailing delimiter
>          v.push_back(str.substr(start, pos - start));
>      }
>      return v;
> }
>
>
> int main(int argc, char* argv[])
> {
>      string str = "this,is,a,test, of whatever, like, ok.";
>      vector<string> v = split<string>(str, ", ");
>      for (int i = 0; i < v.size(); ++i) {
>          cout << v[i] << endl;
>      }
> }
>
>

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