Re: C++0x syntax question

Hi Kelly,

According to the C++ standard (see below), the error messages are expected.
'typename' should be added.

  14.6 Name resolution

  2  A name used in a template declaration or definition and that is
     dependent on a template-parameter is assumed not to name a type
     unless the applicable name lookup finds a type name or the name
     is qualified by the keyword typename.

The diagnostic message from ILE C++ compiler with option LANGLVL
(*EXTENDED0X) is not as clear as the messages from g++ compiler.

We need more investigation on the reason why the compiler does not generate
diagnostic message without LANGLVL(*EXTENDED0X).

Thanks.


Qian Ren (Jarod)



From:	Kelly Beard <[email protected]>
To:	"Bare Metal Programming IBM i (AS/400 and iSeries)"
            <c400-l-Zwy7GipZuJhWk0Htik3J/[email protected]>
Date:	09/13/2017 12:06 AM
Subject:	Re: [C400-L] C++0x syntax question
Sent by:	"C400-L" <c400-l-bounces-Zwy7GipZuJhWk0Htik3J/[email protected]>



per my question, this does seem to be a change in syntax in the language.
 g++ is more clear and complete in it's error reporting.  For the newer
stuff, the word "typename" should appear appear in front of the offending
line.  The corrected code is:

#include <iostream>
#include <string>
#include <sstream>
#include <iomanip>
#include <vector>
#include <unistd.h>

using namespace std;


template<typename T> vector<T> split(const T & str, const T & delimiters)
{
    vector<T> v;
    typename T::size_type start = 0;
    size_t pos = str.find_first_of(delimiters, start);
    while (pos != T::npos) {
        if (pos != start) { // ignore empty tokens
            v.push_back(str.substr(start, pos - start));
        }
        start = pos + 1;
        pos = str.find_first_of(delimiters, start);
    }
    if (start < str.length()) { // ignore trailing delimiter
        v.push_back(str.substr(start, pos - start));
    }
    return v;
}


int main(int argc, char* argv[])
{
    string str = "this,is,a,test, of whatever, like, ok.";
    vector<string> v = split<string>(str, ", ");
    for (int i = 0; i < v.size(); ++i) {
        cout << v[i] << endl;
    }
}


On Tue, Sep 12, 2017 at 10:38 AM, Kelly Beard <[email protected]>
wrote:

> Take away the *EXTENDED0X option and it compiles just fine.
>
> On Tue, Sep 12, 2017 at 10:21 AM, Mark S Waterbury <
> [email protected]> wrote:
>
>> Kelly,
>>
>> Did this code ever  compile on IBM i under previous versions of the IBM
>> ILE C++ compiler?
>>
>> IBM does not strictly follow the ANSI standards for either C or C++ ...
>>
>> You could also install the open-source GCC compiler and it would
probably
>> compile this code for you ... of course, the resulting object code would
>> run under PASE ...
>>
>> Mark
>>
>>
>> > On 9/12/2017 10:57 AM, Kelly Beard wrote:
>>
>>> I am attempting to compile the following code under the newer compiler
>>> under V7R3 and the LANGLVL *EXTENDED0X option enabled.  I am using the
>>> 5799PTL 'icc' compiler front-end to do this.  The command default for
>>> CRTCPPMOD has been altered to always have *EXTENDED0X on by default.  I
>>> am
>>> getting this:
>>>
>>> "testme.cpp", line 14.18: CZP0130 (30) "start" is not declared.
>>>
>>> The offending line looks like:
>>>
>>> T::size_type start = 0;
>>>
>>> So, is there a change to the C++11 syntax here?  Thanks in advance, as
>>> always.  Here is the test program.
>>>
>>> #include <iostream>
>>> #include <string>
>>> #include <sstream>
>>> #include <iomanip>
>>> #include <vector>
>>> #include <unistd.h>
>>>
>>> using namespace std;
>>>
>>>
>>> template<typename T> vector<T> split(const T & str, const T &
delimiters)
>>> {
>>>      vector<T> v;
>>>      T::size_type start = 0;
>>>      size_t pos = str.find_first_of(delimiters, start);
>>>      while (pos != T::npos) {
>>>          if (pos != start) { // ignore empty tokens
>>>              v.push_back(str.substr(start, pos - start));
>>>          }
>>>          start = pos + 1;
>>>          pos = str.find_first_of(delimiters, start);
>>>      }
>>>      if (start < str.length()) { // ignore trailing delimiter
>>>          v.push_back(str.substr(start, pos - start));
>>>      }
>>>      return v;
>>> }
>>>
>>>
>>> int main(int argc, char* argv[])
>>> {
>>>      string str = "this,is,a,test, of whatever, like, ok.";
>>>      vector<string> v = split<string>(str, ", ");
>>>      for (int i = 0; i < v.size(); ++i) {
>>>          cout << v[i] << endl;
>>>      }
>>> }
>>>
>>>
>>>
>> --
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 .
>>
>>
>
>
> --
> Kelly Beard
>



--
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