Re: Count records in SQL
x y <[email protected]> Thu, 12 Feb 2026 21:04:18 -0800
| Newsgroups | gmane.comp.lang.as400.rpg |
|---|---|
| Message-ID | <CAHfwH+4F+rhVmqn4LZ-NfnLZY1iYtwNMAWQiZoFdhyw__DYyNw@mail.gmail.com> |
GET DIAGNOSTICS counts the rows just processed (deleted or inserted, for example). It doesn't work on rows just sitting there. <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail> Virus-free.www.avast.com <https://www.avast.com/sig-email?utm_medium=email&utm_source=link&utm_campaign=sig-email&utm_content=webmail> <#DAB4FAD8-2DD7-40BB-A1B8-4E2AA1F9FDF2> On Thu, Feb 12, 2026 at 12:43 PM Jimmy Sansi <[email protected]> wrote: > What about ... > > exec sql GET DIAGNOSTICS :Rows = ROW_COUNT; > > https://www.ibm.com/docs/en/i/7.5.0?topic=statements-get-diagnostics > > On 2026-02-12 12:15, Jerry Forss wrote: > > > I have a SQL > > SqlSelect = 'SELECT C6DcCd, ' + > > 'C6CvNb, '+ > > 'C6AcDt, ' + > > 'C6FnSt,' + > > 'C6B9Cd ' + > > 'From ' + %Trim(PurgeXALib) + '/MBC6REP ' + > > 'Where C6ACDT <= ' + %EditC(PurgeDateCYMD : 'X'); > > > > Instead of reading through the cursor, I want the number of records > > found. > > > > How do I do that? > -- > This is the RPG programming on IBM i (RPG400-L) mailing list > To post a message email: [email protected] > To subscribe, unsubscribe, or change list options, > visit: https://lists.midrange.com/mailman/listinfo/rpg400-l > or email: [email protected] > Before posting, please take a moment to review the archives > at https://archive.midrange.com/rpg400-l. > > Please contact [email protected] for any subscription related > questions. > > -- This is the RPG programming on IBM i (RPG400-L) mailing list To post a message email: [email protected] To subscribe, unsubscribe, or change list options, visit: https://lists.midrange.com/mailman/listinfo/rpg400-l or email: [email protected] Before posting, please take a moment to review the archives at https://archive.midrange.com/rpg400-l. Please contact [email protected] for any subscription related questions.