Re: [stack] A question on joy syntax.

Rahul <[email protected]> wrote:
>      I have been looking through the joy papers, and have
> this confusion:
> 1 5 [1 =] [dup *] [dup +] ifte .
> 10

> The doubt I have is this:
> as soon as [1 =] is executed, I would expect '5' off the stack,
> so the [dup +] should have actually found '1' on the stack and given
> me 2.

Yup. Me too. But that's not what Joy does; some of Joy's combinators
save the stack's state when they're performing certain types of
actions. You simply have to learn which ones do it and which ones
don't.

Sometimes this is very handy. Sometimes it's annoying.

>                            rahul.

-Billy