Re: [stack] Re: Some thoughts on Object Cat

zallambo scripsit:

> Evaluating (eval (quote (1 2 3))) gives precisely the same result as
> evaluating (1 2 3) - an error. Consider instead (eval (quote (+ 2 3))),
> which yields 5, as expected. In general, evaluating (eval (quote X))
> always gives the same result as evaluating X.

In the top-level lexical environment that is.  Eval does not have access
to the lexical environment from which it is invoked.

I think the confusion arises because Christopher thinks of [foo] as a
function, whereas in Joy it is a list of functions, and only a function
because everything in Joy can be treated as a function.  So the effect
of applying the function [foo] to stack S is that we get S [foo] as the
new stack.  The i function does not apply a function to the rest of
the stack, but evaluates in turn all the functions in the list at the
top of the stack, thus implicitly composing them.

-- 
John Cowan                                [email protected]
I amar prestar aen, han mathon ne nen,    http://www.ccil.org/~cowan
han mathon ne chae, a han noston ne 'wilith.  --Galadriel, LOTR:FOTR