Re: mix 2 bitmaps
"Comboy" <[email protected]> Thu, 21 Aug 2003 08:01:27 -0000
| Newsgroups | gmane.comp.lang.delphi.programming |
|---|---|
| Message-ID | <[email protected]> |
hello Rolf, as u know colors are from red blue and green, a grayscale color has=20 got the same value of these 3 colors. for example 200,200,200 is a=20 silver (grayscale) color but 200,200,199 is not. I think you should=20 use this method for your filter: get each color value from the greyscale picture and the colored=20 picture, add them up then div 2 (Average). think, the silver color is 666666 and the rgb color is 3F8F3D, you=20 see 3F is 63 and 8F is 143 and 3D is 61 in dec. ( 66 + 63 ) / 2 =3D 64 -> 40 in hex ( 66 + 143) / 2 =3D 104 -> 68 in hex ( 66 + 61 ) / 2 =3D 63 -> 3F in hex so the mixed color is 40683F. well 666666 is a dark gray and 3F8F3D=20 is a green and the result is a dark green! there are 255 colors in=20 grayscale mode, one is white one is black and 223 colors are silver. Joy, Comboy. > Hi > What I want to do is transfer color from a color image to a=20 greyscale=20 > image. There is a paper called "Transferring Color to Greyscale=20 > Images" and I want to make a program that uses this paper. > The user gives a color image and a greyscale image and the program=20 > transferes colors from the color image to the greyscale... > It=B4s eazy to find the paper in google... > Could you help me? > thank you > Rolf ------------------------ Yahoo! Groups Sponsor ---------------------~--> Buy Ink Cartridges or Refill Kits for Your HP, Epson, Canon or Lexmark Printer at Myinks.com. Free s/h on orders $50 or more to the US & Canada. h= ttp://www.c1tracking.com/l.asp?cid=3D5511 http://us.click.yahoo.com/l.m7sD/LIdGAA/qnsNAA/i7folB/TM ---------------------------------------------------------------------~-> Delphi VCL Top Sites! http://www.sandbrooksoftware.com/TS/TS2/Components.shtml --------------------------------------------------------------- Unsubscribe:[email protected] List owner:[email protected] ---------------------------------------------------------------=20 Your use of Yahoo! Groups is subject to http://docs.yahoo.com/info/terms/=20