Re: Not terminating loop possible with RX_PCRE_REGULAR_EXPRESSION.replace_all

>>>>> "Berend" == Berend de Boer <[email protected]> writes:

    Berend> What happens is that the start position is 1, and the end
    Berend> position is 0. has_matched is always true. I'm not sure
    Berend> how to solve this. This was what I have now:

My previous solution didn't work that well. Here another attempt:

			new_end, previous_end: INTEGER
		do
			old_subject_start := subject_start
			from until not has_matched loop
				STRING_.append_substring_to_string (a_string, subject, subject_start, captured_start_position (0) - 1)
				append_replacement_to_string (a_string, a_replacement)
				previous_end := captured_end_position (0)
				match_substring (subject, previous_end + 1, subject_end)
				new_end := captured_end_position (0)
				if previous_end = new_end then
					-- Get out of loop, we're matching the same thing,
					-- i.e. we're not making any progress.
					match_count := 0
				end
			end

So if the captured_end_position doesn't move, we quite the loop.

-- 
All the best,

Berend de Boer


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