Re: How are words truncated?

Characters are packed into the upper 28-bits of a 32-bit 
word, but the last character may extend the length of the 
characters past 28-bits if the extended bits of the 
character are zero. 'pack' will always pack as many 
characters as possible in a preparsed word.

---- Original message ----
>Date: Mon, 20 Jun 2005 21:52:31 +0200
>From: [email protected] (Albert van der Horst)  
>Subject: [colorforth] How are words truncated?  
>To: colorforth mailing list <[email protected]>
>
>One of the most annoying things remaining in my meta-
assembler is
>the situation with extension words, where a Huffman token 
spans
>two 32 bit longs.
>E.g. screen 18 reads
>
>         (colorf +orth (Jul3 +1  ...
>code     9       0     A     0
>
>This is of course ugly.
>
>Can anybody confirm this rule of splitting :
>- tentatively add one more character.(This may fill in 
below zero bits!)
>- if any bit below 5 is up, (including the below zero bits)
>  it fails, and this character and following spill to the 
next long.
>
>Is it possible or allowed to split differently over longs 
e.g.
>(color +forth (Jul +31
>
>The latter would require that a true meta-assembler could 
not
>always interpret `` (colorforth '' into two tokens in an
>unambiguous way. But it could still allow it as a 
convenience for
>people who don't care.
>
>Thanks!
>
>Groetjes Albert
>
>--
>Albert van der Horst,Oranjestr 8,3511 RA UTRECHT,THE 
NETHERLANDS
>Economic growth -- like all pyramid schemes -- ultimately 
falters.
>[email protected] 
http://home.hccnet.nl/a.w.m.van.der.horst
>
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