Re: Correct parsers for bounded integral values
Jeff Clites via Haskell-Cafe <[email protected]> Sun, 20 Jul 2025 17:24:47 -0700
| Newsgroups | gmane.comp.lang.haskell.cafe |
|---|---|
| Message-ID | <[email protected]> |
> On Jul 20, 2025, at 9:43 AM, Brandon Allbery <[email protected]> wrote: > > I would like to point out that if you want correctness, you should use `Integer`. If you are using a bounded `Integral` it is expected that you are doing so because you value speed over correctness. They are _not_ `Z/n`, they are hardware values that have little to do with formal mathematics. But aren't they de-facto modular integers? Jeff _______________________________________________ Haskell-Cafe mailing list To (un)subscribe, modify options or view archives go to: http://mail.haskell.org/cgi-bin/mailman/listinfo/haskell-cafe Only members subscribed via the mailman list are allowed to post.