Re: How to write *include* like Ruby?

This is something I've been thinking about heavily over the last two days,
so I'm glad to see someone else post about it.

On Sat, May 19, 2012 at 9:48 AM, lijie <[email protected]> wrote:

> **
>
>
> Hi,
>
> I want to write Io code like Ruby meta programming. *Module#include* is an
> important method to extend classes.
>
> In Io, I wrote some code:
>
> include := method (module,
>>   call sender addTrait(module)
>> )
>>
>> Validations := Object clone do (
>>   validate := method(args,
>>     "validate" println
>>   )
>> )
>>
>> Person := Object clone do (
>>   include(Validations)
>> )
>>
>> Person println
>
>
> outputs:
>
>  Validations_0x7fd8a8c8d440:
>
>   type             = "Validations"
>
>   validate         = method(args, ...)
>
>
>
>
> The type of Person is "Validations".
>
> Then I try to call *include* after create Person:
>
> Person := Object clone
>>
>> Person do (
>>   include(Validations)
>> )
>
>
> outputs:
>
>  Person_0x7f90ab496ee0:
>
>   type             = "Person"
>
>   validate         = method(args, ...)
>
>
> This is my expectation. But I want to do all things in the prototype
> creation. How to write the corrective *include* method?
>
>
>  
>