Auto converting Python lambdas to functional interface impl.

Hello dev team,

int foo(BiFunction<Integer, Integer, Integer> f) {
  return f.apply(1, 2);
}
foo((a, b) -> a + b );  // ok

I was wondering if Jython 2.7 would auto-convert to idiomatic lambdas, and
tried:
foo(lambda a, b: a + b)

alas, I got a
TypeError: can't convert <function <lambda> at 0x3> to
java.util.function.BiFunction
(same problem with a single-arg lambda, e.g. foo(lambda (a, b): a + b))

Any plan to support that in a future maintenance release, or maybe for
Jython 3?

Thanks,
--
Nicolas Falliere ([email protected])
JEB Decompiler, Founder and Architect
PNF Software <https://www.pnfsoftware.com/> | Follow us on Twitter
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