Re: Pass int64

Tom, Thanks, 

Yes, your variant works. But what should I do if my class has get method like:
__int64 getSize();

.cpp
luabind::class_<RawData, boost::shared_ptr<RawData> >("RawData" )
    .def( luabind::constructor<int>() )
    .def("getSize", &RawData::getSize) 

.lua
RawData(10):getSize()

I get "you are trying to use an unregistered type".

I tryed something like the next, but I cannot use 'type'. 
luabind::class_< __int64 > ("Int64")

Thanks,
Valery.

----- Original Message ----- 
From: Tom McCubbin 
To: [email protected] 
Sent: Tuesday, May 26, 2009 3:51 PM
Subject: Re: [luabind] Pass int64


If the constructor is not explicit (not marked as so below), why not try and change your luabind::constructor<>()  to take an int, and let the compiler do its 1 allowed conversion step.  At runtime luabind doesn't have the smarts to map a number to __int64 in looking up the constructor would be my guess as to why you have the problem.

luabind::class_<RawData, boost::shared_ptr<RawData> >("RawData" )
    .def( luabind::constructor<int>() ); //...

That or derive and add a new signature for int.


On Tue, 2009-05-26 at 14:32 +0300, Valery wrote: 
Hello,

I have a class that gets __int64 as a parameter in the constructor. I am 
trying to create it from lua, but get the error "FAIL: Test: no constructor 
of 'RawData' matched the arguments (number)
 candidates are:
RawData(custom [__int64])"

Could anybody help?

.cpp
class RawData {
 public: RawData(__int64) {}
};
luabind::class_<RawData, boost::shared_ptr<RawData> >("RawData")
 .def(luabind::constructor<__int64>())

.lua
x=RawData(10)

Thanks,
Valery. 


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