Re: Using luabind wrapped types as keys into lua tables

That does the trick. I templated it so I can apply it to other classes:

template <class T>
 void GetRawKey(lua_State* L, const T & p)
 {
     lua_pushlightuserdata(L, (void *)&p);
 }

Thanks!

On Thu, Mar 4, 2010 at 6:29 PM, Daniel Wallin <[email protected]> wrote:

> On Thu, Mar 04, 2010 at 02:28:41PM +1100, Greg Santucci wrote:
> > Any type can be used as a key in a lua table, so I'd like to use
> > references to luabind wrapped types. The problem is that different lua
> > variables pointing to the same luabind C++ data are going to be seen
> > as different keys from the point of view of a lua table. For example:
> >
> > mypin = c.pins:at(0)
> > mypin2 = c.pins:at(0)
> >
> > pinmap = {}
> > pinmap[mypin] = "hello"
> > print(pinmap[mypin2]) -- Results in (null) printed.
> >
> > -- But:
> >
> > mypin = c.pins:at(0)
> > mypin2 = mypin
> > pinmap[mypin] = "hello"
> > pinr(pinmap[mypin2]) -- Results in "hello" printed, no problem
> >
> > mypin and mypin2 can't be used as the same key from the point of view
> > of a lua table.
> >
> > Is there a way to get to the raw data pointer, so that can be used as a
> key
> > instead?
>
> You could write a small function that returns it:
>
>  void get_raw_key(lua_State* L, pin const& p)
>  {
>      lua_pushlightuserdata(L, &p);
>  }
>
>  ...
>
>  module(L) [
>      class_<pin>("pin")
>        .def("raw_key", &get_raw_key)
>  ];
>
> --
> Daniel Wallin
> BoostPro Computing
> http://www.boostpro.com
>
>
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