Re: is it possible to obtain the lua state during a call from lua to c++ function via luabind?

Thanks to the magic of luabind, it's actually quite simple...

luabind::object cppfunction( lua_State* l )
{
  //i need a lua state here which invoking thisfunction.

  luabind::object table = luabind::newtable(l);
  table[1]="asdfjkl;";
  return table;
}

bind it as before.

module(l)
[
   def( "cppfunction", &cppfunction )
];

you still call the function from Lua like:

mytable = cppfunction()

luabind recognizes "lua_State*" and removes it from the parameter list
for when calling from Lua.  It then gets supplied by luabind when you
actually call the function from Lua. At least that's how I think it
works from my quick look at the code... ;-)

This and automatic down-casting, are my picks for the "Totally awesome
new feature" award. :-D

Nigel

On Wed, 2010-03-24 at 10:17 +0800, [email protected] wrote:
> consider i have such a function in c++:
> luabind::object cppfunction()
> {
>   lua_State* l; //i need a lua state here which invoking this
> function.
> 
> 
>   luabind::object table = luabind::newtable(l);
>   table[1]="asdfjkl;";
>   return table;
> }
> 
> 
> and it was registered to lua:
> module(l)
> [
>   def("cppfunction",&cppfunction)
> ];
> 
> 
> now how do i obtain the state in my cpp function?is it possible?
> i can not use a singleton luastate,because i need more than one states
> running parallel.
> 
> 
> 
> 
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------------------------------------------------------------------------------
Download Intel® Parallel Studio Eval
Try the new software tools for yourself. Speed compiling, find bugs
proactively, and fine-tune applications for parallel performance.
See why Intel Parallel Studio got high marks during beta.
http://p.sf.net/sfu/intel-sw-dev