Re: How to call a Lua function which has been defined in a table ?

hi Nicolas,

try to pull the function from the table first before calling it:
luabind::object func = luabind::globals["mytable"]["func"];
luabind::call_function<void>(L, func);
In Lua, this would be the dot notation: mytable.func()
If it is a method with implicit "self" parameter then you need to specify it as 
the first one in the call:
luabind::object myobject = luabind::globals["myobject"];
luabind::object func = luabind::globals["myobject"]["func"];
luabind::call_function<void>(L, func, myobject);
This would be equivalent to myobject:func() in Lua (note the colon). Add more 
parameters as required.
Don't forget to check for nil values.
Something like this should work.
Best,
Tony 






________________________________
Von: Nicolas Goles <[email protected]>
An: [email protected]
Gesendet: Montag, den 13. Dezember 2010, 19:39:49 Uhr
Betreff: [luabind] How to call a Lua function which has been defined in a table 
?

Hello!,

I'm trying to call a Lua Function which has been defined inside a     table:

table = {}

function table:test()
    print("Lua Rocks")
end


How can I call that function from C++ ? I'm trying to use luabind::call_function 
resulting in:

terminate called after throwing an instance of 'luabind::error'
  what():  lua runtime error

I tried :

            luabind::call_function<void>(L "table:test",     NULL);

Help is appreciated :)

Thanks.

_Nicolas



-- 
Nicolas Goles Domic
Founder         & Lead Developer
Gando Games

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