Re: Error trying to export class

Hi,
I'm not sure about your first question, I think you should use something
like this :
MyPoint = point2d()

but about your second question I use this :

    luaL_dostring(LuaState,"func(2,3)");
    if (lua_isstring(LuaState, lua_gettop(LuaState))) {
        std::cout << lua_tostring(LuaState,lua_gettop(LuaState)) << "\n";
        lua_pop(LuaState, 1);
    }

----------------------------

Hello all, I have a question. I'm a newbie: First, this is my c++ code
#include <iostream>
#include <cstdlib>

extern "C" {
 #include "lua.h"
 #include "lualib.h"
 #include "lauxlib.h"
}

#include "luabind/luabind.hpp"

using namespace std;

class Point2D{
int _x,_y;
public:
Point2D():_x(0),_y(0){}
void setXYPoint(int x, int y){_x = x; _y = y;}
void printPoint(){std::cout << "X = "<<_x<<" Y = "<<_y<<"\n";}
void publishAPI(const lua_State* L){}
};


int main(){

lua_State *L = lua_open();

// Connect LuaBind to this lua state
luabind::open(L);
luaL_openlibs(L);
luabind::module(L)[
luabind::class_<Point2D>("
point2d")
.def(luabind::constructor<>())
.def("print",&Point2D::printPoint)
.def("setXY",&Point2D::setXYPoint)
];

// Define a lua function that we can call
luaL_dofile(L,"main.lua");
try{
std::cout << "Result: "
<< luabind::call_function<int>(L, "func", 2, 3)
<< endl;
lua_close(L);
}
catch(const std::exception& e){
std::cout << e.what() << std::endl;
}
return EXIT_SUCCESS;

}

And this is my lua script

function func(first, second)
 MyPoint = point2d
  MyPoint:setXY(3,4)
  MyPoint:print()
 return first + second
end

The only result I always get is "lua runtime exception". But the program
compiles fine and it seems legal. Could you help me please? This is very
similar to others samples.

Another question is: how do I get a more detailed error message? I always
get "lua runtime exception" and I need a more comprehensive error

Thanks in advance.
Ferran

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