Re: raw pointer in lua

On Mon, January 9, 2012 11:04 pm, ���� wrote:
> code(C++):

>
luabind::object_cast<bool>(m_luaObject["SetAttribute"](m_luaObject,
this,

> strName, strValue));

>

> m_luaObject is luabind::object type. I call it&#39;s SetAttribute
method��and

> pass the second parameter "this" pointer. I had register
the class of

> "this" in the lua.

> Now, I want to call some method through "this" pointer in
the lua. How can

> I do it?

>

> code(LUA):

> function TextButton:SetAttribute(object, name, value)

> object.InternalFindUIObject("caption") -- "this"
pointer, how can

> I user here?

> end
You should be able to
call:
 
this:method()
 
Depending on
what you have registered for the class that &#39;this&#39; is an instance
of.
I&#39;ve attached a small
example.
Nigel
 
>

>

> Thanks!

>
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#include <luabind/luabind.hpp>
#include <iostream>
#include <lua.hpp>

using namespace luabind;
using namespace std;

class Item
{
    public:

    string name;

    Item( string n ) { name = n; }

    void printString() { cout << "Item: " << name << endl; }
};

int main()
{
    lua_State* L = lua_open();

    luaL_openlibs( L );
    luabind::open(L);

    module(L)
    [
        class_<Item>( "Item" )
        .def( constructor<string>() )
        .def( "printString", &Item::printString )
    ];

    const char *script =
        "class 'zing'\n"
        "function zing:splat( object )\n"
        "   object:printString()\n"
        "end\n"
        "function zing:__init()\n"
        "   print 'Created a zing'\n"
        "end\n"
        "myzing = zing()\n";

    if( luaL_dostring( L, script ) )
        cout << lua_tostring( L, -1 ) << endl;

    Item item( "An item" );

    // This scope is so 'myzing' goes out of scope and destructs
    // before lua_close is called.
    // Otherwise you get trouble.
    {
        object myzing = globals(L)["zing"];

        myzing["splat"]( myzing, item );
    }

    lua_close( L );

    return 0;
}