Factories as script constructors.

I have a C++ class that I want to export to Lua.  This class requires a factory method to construct and I would like to hide this little detail from the script side of things.

If my class looks like this:

class Foo
{
    public:
        static boost::shared_ptr<Foo> factoryFoo( int N );
		
        void doSomething( );
    protected:
        Foo() ;
};

module(L)
[
    class_<Foo, boost::shared_ptr<Foo> >("LuaFoo")
        .factory(&Foo::factoryFoo)
        .def("doSomething", &Foo::doSomething)
];

From the script I would be able to do the following:

myF = LuaFoo( 5 ) -- Actually calls the static method Foo::factoryFoo&nbsp;
myF:doSomething()

Has anyone else done something like this? &nbsp; I’ve gotten quite a ways by cloning and mutating the constructor.hpp implementation and adapting it to call a static member but I’m now getting lost in template expansion hell.&nbsp;

I seem to be encountering two problems:
1)	Figuring out the Signature deduction templates and making my static function “look” like a constructor.
2)	Determining the boost::shared_ptr<foo> when I’m deep inside the factory wrapper.

If anybody has some experience in these areas it would be great.

TomN

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