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Yes, I noticed and I try to understand
the difference :
I think you mean this function :
let rec aux_rev l accum =
DoI understand that this part in aux_rev[] takes care of a empty
acc ?
I find this solution a little bit confusing expecially the in part
.
Roelof
Matthieu Dubuget [email protected] [ocaml_beginners]
schreef op 20-10-2014 19:42:
Have a second look at Chingfan Tsao post.
He gives you the solution.
Yes: l2 was renamed to accum. This is because it is an
accumulator that is growing during the calls, and returns
the result at the end.
You'll notice that inside rev_list_tail_rec, a hidden
function is defined, and called. During this call, accum
is initialized.
Best regards
Le 20/10/2014 17:56, Roelof
Wobben [email protected]
[ocaml_beginners] a écrit :
Oke,
If I look it it seems to me that acc does the same as
l2 on my programm.
But does acc not have to be intialized on some way ?
Sébastien
then the outcome will be :
string list = ["c"; "b"; "a"; "1"; "2"; "3"]
so it reverse the second string and not the first one.
Roelof
Chingfan Tsao [email protected]
[ocaml_beginners] schreef op 20-10-2014 15:55:
Hi,
It is indeed a good way to solve it since
it's tail recursion, however, there's one more
thing to do to make it easier, wrap it with a
more convenient function:
let rev_list_tail_rec l =
let rec aux_rev l accum =
match l with
| [] -> accum
| h :: tl ->
aux_rev tl (h::accum)
in
aux_rev l []
this way, you can just use rev_list_tail_rec
l instead of having to give one more [] as the
initial value of the accumulator.
2014-10-20 18:56
GMT+08:00 Roelof Wobben [email protected]
[ocaml_beginners] <[email protected] >:
Hello,
I try the 99 ocaml problems and have
solved the reverse a list problem.
My solution looks like this :
let rec test l1 l2 =
match l1 with
| [] -> l2
| h :: t -> test t (h::l2)
;;
Is this a good way to solve it or
are there things that can be better
?
Roelof
--
曹竞帆
哈尔滨工业大学计算机科学与技术专业本科在读
哈尔滨工业大学IBMTC成员
--
Matthieu Dubuget
Guide d’autodéfense numérique : http://guide.boum.org
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Posted by: Roelof Wobben <[email protected]>
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