Re: Where is the syntax error

Hi,


> As a exercise of Ocaml from the very beginning I have to write
> a function which display true if both are non zero .> 
> So I tried this : 
> 
> let both_zero a b = a != 0 || b !=0   ;;


Besides the problems with using the wrong intepreter and using
physical inequality (!=) instead of structural inequality (<>),
there's also another problem with your code: why is the function
called "both_zero" when its semantics imply that "both_non_zero"
should actually be its name?

Btw, regarding the physical/structural equality/inequality operators:
as a beginner, you should never come across a situation where you
actually need the physical eq/neq operators.  Try to get them out
of your mind for now, and always use the structural eq/neq operators
until your mastery of the language reaches a point where you really
grok the difference between them.


Best regards,
Dario Teixeira