Re: Bytes module versus String module.

"Douglas Lewit [email protected] [ocaml_beginners]" <[email protected]> Wed, 8 Feb 2017 13:48:44 -0600
Newsgroups gmane.comp.lang.ocaml.beginners
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Thanks Gabriel.... that made a lot of sense.  I tried my function on a
string containing almost 56, 000 words ( so way more than 56, 000
characters ) and it took the function a couple minutes to process
everything.  I also tried:

*#load "str.cma" ;;*

*Str.split ( Str.regexp "[ ]+" ) my_string *

and this took less than a second!

Your comment was interesting.....* manipulate the indices of the string
rather than the string object itself*.  Do you think this is normally the
best practice for manipulating strings in OCaml?

You mentioned that you have students.  I hope my question isn't too
personal, but I am curious about where you teach.  Are you a computer
science teacher?  Or math teacher?  Engineering teacher?  How long have you
been teaching?

Thanks and have a great day.

Best,

Douglas.


On Wed, Feb 8, 2017 at 10:12 AM, Gabriel Scherer [email protected]
[ocaml_beginners] <[email protected]> wrote:

>
>
> Because computing the tail takes time and space linear in the size of the
> tail, repeatedly computing the tail of a string is quadratic: (tail
> "Gabriel") allocates (at least) 6 bytes, (tail "abriel") 5 bytes, (tail
> "briel") 4 bytes, etc., in total you allocate (at least) 21 bytes just to
> traverse a string of 7 characters (in general it's n*(n-1)/2). On the
> contrary, taking the tail of a list returns instantly and allocates nothi=
ng
> (in OCaml; for Python, you might be in trouble, although it's hard to tel=
l
> as common operations are optimized, muddying the performance mental model=
).
>
> You can write code more efficiently without using a more powerful library
> (String or other), just using a programming style that is more suited to
> lists. My advice to my students (that always start by falling in the same
> pitfall as you) is to manipulate *indices* in the string, rather than the
> string directly, in their recursive manipulations.
>
> In the case of your example, I would propose for example the following
> structure:
>
> let remove_spaces str =3D
>   let len =3D String.length str in
>   let word start cur =3D
>     String.sub str start (cur - start) in
>   let rec skip i acc =3D
>     ...
>   and read start cur acc =3D
>     ...
>   in
>   List.rev (skip 0 [])
>
> where (skip i acc) skips characters that are spaces (it's parameter (i) i=
s
> the first character to look at), and (read start cur acc) reads a word:
> (start) is the position of the first letter already found in the word,
> (cur) is the current position to examine (it may be a letter, in which ca=
se
> the words continue, or a space, in which case the word is complete). (acc=
)
> is the accumulator, the list of words found previously (in reverse order)=
.
> (skip) calls (read) when it finds a non-space; when (read) finds a space,
> it adds a word to (acc) and calls (skip). Finally, (word start cur) is
> called when (start) is known to be the first non-space character of a wor=
d
> and (cur) is known to be the first space character after a word, and
> returns the word.
>
> (It is possible to traverse the string in the reverse order, from end to
> beginning, to avoid having to reverse the accumulator in the end. But I
> find it easier to program in this way; then I can always derive the
> reversed version from it if I want to be even more efficient. The reverse=
d
> version uses a (word) function with different assumptions, (word cur stop=
),
> where (cur) is known to be the first space before a word and  (stop) the
> last position of a character in the word, so its code is a bit different)=
.
>
>
> On Wed, Feb 8, 2017 at 4:27 PM, Douglas Lewit [email protected]
> [ocaml_beginners] <[email protected]> wrote:
>
>>
>>
>> Hi Gabriel,
>>
>> I appreciate the feedback.  A couple questions.... first off, regarding
>> the -safe-string flag.... is that an option only for compiling OCaml cod=
e?
>> Or can that be entered into the top level ( for example, utop ) ?
>>
>> Yes, I really do enjoy the recursive treatment of lists.  OCaml provided
>> my first experience with the head/tail paradigm of list-processing,
>> although I have found that the same paradigm can be applied to lists in
>> Ruby and Python as well, although in Ruby and Python the syntax is lucki=
ly
>> simpler than in OCaml.  In Python for example if I have a list, called l=
st,
>> I can do:
>>
>> head =3D lst[0]
>> tail    =3D lst[1:]
>>
>> and from there I can build my recursive algorithm.
>>
>> Also, I've been playing around with Haskell a little ( although I am by
>> no means a Haskell pro ) and in that language strings are really lists o=
f
>> chars, so any recursive algorithm that you can apply to a list can also =
be
>> applied to a string because in Haskell strings are really lists.
>>
>> Yes, you're right about matching on chars.  I don't know why I felt the
>> need to match on a string instead, but.... oh well.
>>
>> Regarding your first criticism of my function.... I'm not sure I follow
>> you on that one.  Let's say you have a string called "Gabriel".  It seem=
s
>> that the head/tail analysis of the string should be pretty efficient.  S=
o
>> for example:
>>
>> head "Gabriel" ---> "G"
>> tail    "Gabriel" ---> "abriel"
>>
>> and I keep repeating until finally I have:
>>
>> head "l"  ---> "l"
>> tail    "l"  --->  ""  ( the empty string )
>>
>> It seems logical that for the sake of string manipulation the natural
>> base case should be the empty string, just as the empty list often provi=
des
>> the base case for recursive algorithms that are implemented on lists.
>>
>> Is there a more efficient approach?  I know the Str module contains some
>> shortcuts, but I don't like to depend on too many shortcuts.  It's more =
fun
>> to design and implement my own algorithms for solving some of these
>> problems, although in a pinch shortcuts are great.
>>
>> Best,
>>
>> Douglas.
>>
>>
>>
>> On Tue, Feb 7, 2017 at 5:42 PM, Gabriel Scherer [email protected]=
m
>> [ocaml_beginners] <[email protected]> wrote:
>>
>>>
>>>
>>> String represents (immutable) text, while Bytes represent (mutable)
>>> arrays of bytes. Right now, we are in a transition period where the str=
ing
>>> type played both roles, and in particular was always mutable (which is =
not
>>> a very good idea): by default, during this transition period, the two t=
ypes
>>> `string` and `bytes` are compatible (you can use functions of one on th=
e
>>> other). If you enable the `-safe-string` flag, then the two types will =
be
>>> considered incompatible; using it in your code is good practice, and it
>>> will become the default in a future OCaml version.
>>>
>>> Regarding your code:
>>> - repeatedly calling String.sub is inefficient; you want to count the
>>> number of spaces at the beginning and call String.sub just once
>>> - there is no need to use String.make here, you can match on a characte=
r
>>> directly ('c' instead of "c")
>>>
>>> Your code is relatively typical of people that enjoy recursively
>>> processing lists, and try to apply the same approach to strings. Becaus=
e
>>> the "tail" operation on strings takes linear (O(n)) instead of constant
>>> (O(1)) time, this is not a very good idea performance-wise. Reading
>>> characters at any position is fine, but the rest (String.sub, string
>>> concatenation (^)...) should be used as sparsely as possible -- prefera=
bly
>>> not at each recursive call.
>>>
>>> On Tue, Feb 7, 2017 at 11:35 PM, Douglas Lewit [email protected]
>>> [ocaml_beginners] <[email protected]> wrote:
>>>
>>>>
>>>>
>>>> Hi everyone,
>>>>
>>>> I wrote the following functions.
>>>>
>>>>
>>>> *(* The function removeSpacesFromString' relies on the function
>>>> removeSpacesFromString.  removeSpacesFromString' takes a string *
>>>> *   such as "How are you doing" and parses it into a list of separate
>>>> words.  In this case for example, removeSpacesFromString' *
>>>> *   will return ["How"; "are"; "you"; "doing"]. *)*
>>>>
>>>>
>>>> *let rec removeSpacesFromString s w l =3D match Bytes.length s with *
>>>> *                                              |0 -> List.rev begin [w=
]
>>>> :: l end*
>>>> *                                              |_ -> match Bytes.make =
1
>>>> ( Bytes.get s 0 ) with *
>>>> *                                                    |" " ->
>>>> removeSpacesFromString ( Bytes.sub s 1 ( Bytes.length s - 1 ) )  ""  *=
*([w]
>>>> :: l)*
>>>> *                                                    |_   ->
>>>> removeSpacesFromString ( Bytes.sub s 1 ( Bytes.length s - 1 ) ) *
>>>> *                                                               begin =
w
>>>> ^ ( Bytes.make 1 ( Bytes.get s 0 ) )  end l ;;*
>>>>
>>>>
>>>> *let removeSpacesFromString' s =3D List.flatten begin
>>>> removeSpacesFromString s "" [] end ;;*
>>>>
>>>>
>>>> The functions work exactly as I want them to, which is great!  But jus=
t
>>>> for the sake of experimentation I tried to substitute the "String" mod=
ule
>>>> for the "Bytes" module into the first function above.  Well guess what=
?
>>>> Nothing really changed!  I still get the exact same results as before,
>>>> which leads to an interesting question.  How is the Bytes module diffe=
rent
>>>> from the String module?  I sort of get the impression from the online
>>>> documentation that the Bytes module is the "new and improved" version =
of
>>>> the String module, but if that's the case then why doesn't INRIA just
>>>> delete the String module from OCaml's Standard Library?  Are the two
>>>> libraries pretty much the same?  How is the Bytes library better than =
the
>>>> String library?  What would happen if INRIA just decided to remove the
>>>> String library from the next major version of OCaml?
>>>>
>>>> One quick question here before I send my email.  How much does OCaml
>>>> depend on C?  I know that Python and Ruby are essentially very large "=
C
>>>> applications" in the sense that the interpreters for those languages a=
re
>>>> coded in the C language.  ( Or at least that's what I have read online=
. )
>>>>  What about OCaml.  How is OCaml's compiler implemented?  Is the OCaml
>>>> compiler written in C?  Or written in something else?
>>>>
>>>> I appreciate your feedback and thanks!
>>>>
>>>> Best,
>>>>
>>>> Douglas Lewit
>>>>
>>>>
>>>>
>>>>
>>>
>>
>>
>>
>=20
>

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      <p><div dir=3D"ltr"><font size=3D"4">Thanks Gabriel.... that made a l=
ot of sense.=C2=A0 I tried my function on a string containing almost 56, 00=
0 words ( so way more than 56, 000 characters ) and it took the function a =
couple minutes to process everything.=C2=A0 I also tried:</font><div><font =
size=3D"4"><br></font></div><div><font size=3D"4"><b>#load &quot;str.cma&qu=
ot; ;;</b></font></div><div><font size=3D"4"><b><br></b></font></div><div><=
font size=3D"4"><b>Str.split ( Str.regexp &quot;[ ]&#43;&quot; ) my_string=
=C2=A0</b></font></div><div><font size=3D"4"><br></font></div><div><font si=
ze=3D"4">and this took less than a second!=C2=A0</font></div><div><font siz=
e=3D"4"><br></font></div><div><font size=3D"4">Your comment was interesting=
.....<i> manipulate the indices of the string rather than the string object=
 itself</i>.=C2=A0 Do you think this is normally the best practice for mani=
pulating strings in OCaml?</font></div><div><font size=3D"4"><br></font></d=
iv><div><font size=3D"4">You mentioned that you have students.=C2=A0 I hope=
 my question isn&#39;t too personal, but I am curious about where you teach=
.=C2=A0 Are you a computer science teacher?=C2=A0 Or math teacher?=C2=A0 En=
gineering teacher?=C2=A0 How long have you been teaching? =C2=A0</font></di=
v><div><font size=3D"4"><br></font></div><div><font size=3D"4">Thanks and h=
ave a great day.</font></div><div><font size=3D"4"><br></font></div><div><f=
ont size=3D"4">Best,</font></div><div><font size=3D"4"><br></font></div><di=
v><font size=3D"4">Douglas.</font></div><div><font size=3D"4">=C2=A0=C2=A0<=
/font></div></div><div class=3D"gmail_extra"><br><div class=3D"gmail_quote"=
>On Wed, Feb 8, 2017 at 10:12 AM, Gabriel Scherer <a href=3D"mailto:gabriel=
[email protected]">[email protected]</a> [ocaml_beginners] <span d=
ir=3D"ltr">&lt;<a href=3D"mailto:[email protected]" target=3D=
"_blank">[email protected]</a>&gt;</span> wrote:<br><blockquo=
te class=3D"gmail_quote" style=3D"border-left:1px #ccc solid;">


<u></u>









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      <p></p><div dir=3D"ltr"><div><div><div>Because computing the tail tak=
es time and space linear in the size of the tail, repeatedly computing the =
tail of a string is quadratic: (tail &quot;Gabriel&quot;) allocates (at lea=
st) 6 bytes, (tail &quot;abriel&quot;) 5 bytes, (tail &quot;briel&quot;) 4 =
bytes, etc., in total you allocate (at least) 21 bytes just to traverse a s=
tring of 7 characters (in general it&#39;s n*(n-1)/2). On the contrary, tak=
ing the tail of a list returns instantly and allocates nothing (in OCaml; f=
or Python, you might be in trouble, although it&#39;s hard to tell as commo=
n operations are optimized, muddying the performance mental model).<br><br>=
</div>You can write code more efficiently without using a more powerful lib=
rary (String or other), just using a programming style that is more suited =
to lists. My advice to my students (that always start by falling in the sam=
e pitfall as you) is to manipulate *indices* in the string, rather than the=
 string directly, in their recursive manipulations.<br><br>In the case of y=
our example, I  would propose for example the following structure:<br><br>l=
et remove_spaces str =3D<br>=C2=A0 let len =3D String.length str in<br>=C2=
=A0 let word start cur =3D<br>=C2=A0=C2=A0=C2=A0 String.sub str start (cur =
- start) in<br>=C2=A0 let rec skip i acc =3D<br>=C2=A0=C2=A0=C2=A0 ...<br>=
=C2=A0 and read start cur acc =3D<br>=C2=A0=C2=A0=C2=A0 ...<br>=C2=A0 in<br=
>=C2=A0 List.rev (skip 0 [])<br><br></div><div>where (skip i acc) skips  ch=
aracters that are spaces (it&#39;s parameter (i) is the first character to =
look at), and (read start cur acc) reads a word: (start) is the position of=
 the first letter already found in the word, (cur) is the current position =
to examine (it may be a letter, in which case the words continue, or a spac=
e, in which case the word is complete). (acc) is the accumulator, the list =
of words found previously (in reverse order). (skip) calls (read) when it f=
inds a non-space; when (read) finds a space, it adds a word to (acc) and ca=
lls (skip). Finally, (word start cur) is called when (start) is known to be=
 the first non-space character of a word and (cur) is known to be the first=
 space character after a word, and returns the word.<br><br></div><div>(It =
is possible to traverse the string in the reverse order, from end to beginn=
ing, to avoid having to reverse the accumulator in the end. But I find it e=
asier to program in this way; then I can always derive the reversed version=
 from it if I want to be even more efficient. The reversed version uses a (=
word) function with different assumptions, (word cur stop), where (cur) is =
known to be the first space before a word and=C2=A0 (stop) the last positio=
n of a character in the word, so its code is a bit different).<br></div><di=
v><br></div></div></div><div><div class=3D"h5"><div class=3D"gmail_extra"><=
br><div class=3D"gmail_quote">On Wed, Feb 8, 2017 at 4:27 PM, Douglas Lewit=
 <a href=3D"mailto:[email protected]" target=3D"_blank">[email protected]</=
a> [ocaml_beginners] <span dir=3D"ltr">&lt;<a href=3D"mailto:ocaml_beginner=
[email protected]" target=3D"_blank">ocaml_beginners@yahoogroups.<wbr>com</=
a>&gt;</span> wrote:<br><blockquote class=3D"gmail_quote" style=3D"border-l=
eft:1px #ccc solid;">






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<br><br>




<div dir=3D"ltr"><font size=3D"4">Hi Gabriel,</font><div><font size=3D"4"><=
br></font></div><div><font size=3D"4">I appreciate the feedback.=C2=A0 A co=
uple questions.... first off, regarding the -safe-string flag.... is that a=
n option only for compiling OCaml code?=C2=A0 Or can that be entered into t=
he top level ( for example, utop ) ? =C2=A0</font></div><div><font size=3D"=
4"><br></font></div><div><font size=3D"4">Yes, I really do enjoy the recurs=
ive treatment of lists.=C2=A0 OCaml provided my first experience with the h=
ead/tail paradigm of list-processing, although I have found that the same p=
aradigm can be applied to lists in Ruby and Python as well, although in Rub=
y and Python the syntax is luckily simpler than in OCaml.=C2=A0 In Python f=
or example if I have a list, called lst, I can do:</font></div><div><font s=
ize=3D"4"><br></font></div><div><font size=3D"4">head =3D lst[0]</font></di=
v><div><font size=3D"4">tail =C2=A0 =C2=A0=3D lst[1:]</font></div><div><fon=
t size=3D"4"><br></font></div><div><font size=3D"4">and from there I can bu=
ild my recursive algorithm. =C2=A0</font></div><div><font size=3D"4"><br></=
font></div><div><font size=3D"4">Also, I&#39;ve been playing around with Ha=
skell a little ( although I am by no means a Haskell pro ) and in that lang=
uage strings are really lists of chars, so any recursive algorithm that you=
 can apply to a list can also be applied to a string because in Haskell str=
ings are really lists.</font></div><div><font size=3D"4"><br></font></div><=
div><font size=3D"4">Yes, you&#39;re right about matching on chars.=C2=A0 I=
 don&#39;t know why I felt the need to match on a string instead, but.... o=
h well.</font></div><div><font size=3D"4"><br></font></div><div><font size=
=3D"4">Regarding your first criticism of my function.... I&#39;m not sure I=
 follow you on that one.=C2=A0 Let&#39;s say you have a string called &quot=
;Gabriel&quot;.=C2=A0 It seems that the head/tail analysis of the string sh=
ould be pretty efficient.=C2=A0 So for example:</font></div><div><font size=
=3D"4"><br></font></div><div><font size=3D"4">head &quot;Gabriel&quot; ---&=
gt; &quot;G&quot;</font></div><div><font size=3D"4">tail =C2=A0 =C2=A0&quot=
;Gabriel&quot; ---&gt; &quot;abriel&quot;</font></div><div><font size=3D"4"=
><br></font></div><div><font size=3D"4">and I keep repeating until finally =
I have:</font></div><div><font size=3D"4"><br></font></div><div><font size=
=3D"4">head &quot;l&quot; =C2=A0---&gt; &quot;l&quot;</font></div><div><fon=
t size=3D"4">tail =C2=A0 =C2=A0&quot;l&quot; =C2=A0---&gt; =C2=A0&quot;&quo=
t; =C2=A0( the empty string )</font></div><div><font size=3D"4"><br></font>=
</div><div><font size=3D"4">It seems logical that for the sake of string ma=
nipulation the natural base case should be the empty string, just as the em=
pty list often provides the base case for recursive algorithms that are imp=
lemented on lists.</font></div><div><font size=3D"4"><br></font></div><div>=
<font size=3D"4">Is there a more efficient approach?=C2=A0 I know the Str m=
odule contains some shortcuts, but I don&#39;t like to depend on too many s=
hortcuts.=C2=A0 It&#39;s more fun to design and implement my own algorithms=
 for solving some of these problems, although in a pinch shortcuts are grea=
t.</font></div><div><font size=3D"4"><br></font></div><div><font size=3D"4"=
>Best,</font></div><div><font size=3D"4"><br></font></div><div><font size=
=3D"4">Douglas.</font></div><div><font size=3D"4"><br></font></div><div><fo=
nt size=3D"4">=C2=A0=C2=A0</font></div></div><div><div class=3D"m_417982758=
9697787686h5"><div class=3D"gmail_extra"><br><div class=3D"gmail_quote">On =
Tue, Feb 7, 2017 at 5:42 PM, Gabriel Scherer <a href=3D"mailto:gabriel.sche=
[email protected]" target=3D"_blank">[email protected]</a> [ocaml_begin=
ners] <span dir=3D"ltr">&lt;<a href=3D"mailto:[email protected]=
om" target=3D"_blank">[email protected]<wbr>om</a>&gt;</span> w=
rote:<br><blockquote class=3D"gmail_quote" style=3D"border-left:1px #ccc so=
lid;">


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      <p></p><div dir=3D"ltr"><div><div><div><div>String represents (immuta=
ble) text, while Bytes represent (mutable) arrays of bytes. Right now, we a=
re in a transition period where the string type played both roles, and in p=
articular  was always mutable (which is not a very good idea): by default, =
during this transition period, the two types `string` and `bytes` are compa=
tible (you can use functions of one on the other). If you enable the `-safe=
-string` flag, then the two types will be considered incompatible; using it=
 in your code is good practice, and it will become the default in a future =
OCaml version.<br><br></div>Regarding your code:<br></div>- repeatedly call=
ing String.sub is inefficient; you want to count the number of spaces at th=
e beginning and call String.sub just once<br></div>- there is no need to us=
e String.make here, you can match on a character directly (&#39;c&#39; inst=
ead of &quot;c&quot;)<br><br></div>Your code is relatively typical of peopl=
e that enjoy recursively processing lists, and try to apply the same approa=
ch to strings. Because the &quot;tail&quot; operation on strings takes line=
ar (O(n)) instead of constant (O(1)) time, this is not a very good idea per=
formance-wise. Reading characters at any position is fine, but the rest (St=
ring.sub, string concatenation (^)...) should be used as sparsely as possib=
le -- preferably not at each recursive call.<br></div><span><div class=3D"g=
mail_extra"><br><div class=3D"gmail_quote">On Tue, Feb 7, 2017 at 11:35 PM,=
 Douglas Lewit <a href=3D"mailto:[email protected]" target=3D"_blank">delew=
[email protected]</a> [ocaml_beginners] <span dir=3D"ltr">&lt;<a href=3D"mailto:=
[email protected]" target=3D"_blank">ocaml_beginners@yahoogro=
ups.c<wbr>om</a>&gt;</span> wrote:<br><blockquote class=3D"gmail_quote" sty=
le=3D"border-left:1px #ccc solid;">






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<br><br>




<div dir=3D"ltr"><font size=3D"4">Hi everyone,</font><div><font size=3D"4">=
<br></font></div><div><font size=3D"4">I wrote the following functions.</fo=
nt></div><div><font size=3D"4"><br></font></div><div><font size=3D"4" color=
=3D"#cc0000"><b><br></b></font></div><div><font size=3D"4"><div><b><font co=
lor=3D"#20124d">(* The function removeSpacesFromString&#39; relies on the f=
unction removeSpacesFromString. =C2=A0removeSpacesFromString&#39; takes a s=
tring=C2=A0</font></b></div><div><b><font color=3D"#20124d">=C2=A0 =C2=A0su=
ch as &quot;How are you doing&quot; and parses it into a list of separate w=
ords.=C2=A0 In this case for example, removeSpacesFromString&#39;=C2=A0</fo=
nt></b></div><div><b><font color=3D"#20124d">=C2=A0 =C2=A0will return [&quo=
t;How&quot;; &quot;are&quot;; &quot;you&quot;; &quot;doing&quot;]. *)</font=
></b></div><div><b><font color=3D"#20124d"><br></font></b></div><div><b><fo=
nt color=3D"#20124d"><br></font></b></div><div><b><font color=3D"#20124d">l=
et rec removeSpacesFromString s w l =3D match Bytes.length s with=C2=A0</fo=
nt></b></div><div><b><font color=3D"#20124d">=C2=A0 =C2=A0 =C2=A0 =C2=A0 =
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 |0 -&gt; List.r=
ev begin [w] :: l end</font></b></div><div><b><font color=3D"#20124d">=C2=
=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0 =C2=A0 |_ -&gt; match Bytes.make 1 ( Bytes.get s 0 ) with=C2=A0</font><=
/b></div><div><b><font color=3D"#20124d">=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0=
 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 |=
&quot; &quot; -&gt; removeSpacesFromString ( Bytes.sub s 1 ( Bytes.length s=
 - 1 ) ) =C2=A0&quot;&quot; =C2=A0</font></b><b><font color=3D"#20124d">([w=
] :: l)</font></b></div><div><b><font color=3D"#20124d">=C2=A0 =C2=A0 =C2=
=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0 =C2=A0 =C2=A0 |_ =C2=A0 -&gt; removeSpacesFromString ( Bytes.sub s 1 ( =
Bytes.length s - 1 ) )=C2=A0</font></b></div><div><b><font color=3D"#20124d=
">=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =
=C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=A0 =C2=
=A0begin w ^ ( Bytes.make 1 ( Bytes.get s 0 ) ) =C2=A0end l ;;</font></b></=
div><div><b><font color=3D"#20124d"><br></font></b></div><div><b><font colo=
r=3D"#20124d"><br></font></b></div><div><b><font color=3D"#20124d">let remo=
veSpacesFromString&#39; s =3D List.flatten begin removeSpacesFromString s &=
quot;&quot; [] end ;;</font></b></div><div><b><font color=3D"#cc0000"><br><=
/font></b></div><div><br></div><div>The functions work exactly as I want th=
em to, which is great!=C2=A0 But just for the sake of experimentation I tri=
ed to substitute the &quot;String&quot; module for the &quot;Bytes&quot; mo=
dule into the first function above.=C2=A0 Well guess what?=C2=A0 Nothing re=
ally changed!=C2=A0 I still get the exact same results as before, which lea=
ds to an interesting question.=C2=A0 How is the Bytes module different from=
 the String module?=C2=A0 I sort of get the impression from the online docu=
mentation that the Bytes module is the &quot;new and improved&quot; version=
 of the String module, but if that&#39;s the case then why doesn&#39;t INRI=
A just delete the String module from OCaml&#39;s Standard Library?=C2=A0 Ar=
e the two libraries pretty much the same?=C2=A0 How is the Bytes library be=
tter than the String library?=C2=A0 What would happen if INRIA just decided=
 to remove the String library from the next major version of OCaml?</div><d=
iv><br></div><div>One quick question here before I send my email.=C2=A0 How=
 much does OCaml depend on C?=C2=A0 I know that Python and Ruby are essenti=
ally very large &quot;C applications&quot; in the sense that the interprete=
rs for those languages are coded in the C language. =C2=A0( Or at least tha=
t&#39;s what I have read online. ) =C2=A0What about OCaml.=C2=A0 How is OCa=
ml&#39;s compiler implemented?=C2=A0 Is the OCaml compiler written in C?=C2=
=A0 Or written in something else?</div><div><br></div><div>I appreciate you=
r feedback and thanks!</div><div><br></div><div>Best,</div><div><br></div><=
div>Douglas Lewit</div><div><br></div></font></div></div>






<br>


<br>




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</html>
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