Re: "Secret" operators

Le mardi 01 février 2005 à 17:40, José Castro écrivait:
> * Ronald J Kimball ([email protected]) wrote:
> > You can assign two elements to a one-element list:
> > 
> > ($foo) = (1, 2);
> > 
> > You can even assign two elements to an empty list:
> > 
> > () = (1, 2);
> > 
> > 
> > In each case, any extra elements are simply discarded, but the result of
> > the assignment in scalar context is always the number of elements on the
> > right-hand side, even if some aren't actually assigned to variables.
> 
> Which is why this:
> 
> perl -e '$_ = ($foo) = (1, 2) ; print'
> 
> prints out 2.

I think a better example is :

    $ perl -e '$_ = ($foo) = (1,3); print'
    2

versus

    $ perl -e '$_ = $foo = (1,3); print'
    3

There you can see how () was useful, and be reminded that a list in
scalar context returns its last element.

-- 
 Philippe "BooK" Bruhat

 The right answer is worthless with the wrong question!
                                    (Moral from Groo The Wanderer #88 (Epic))