Re: The sperm secret operator: is it new?

Sebastian Schmidt <[email protected]> Wed, 14 Mar 2012 15:51:09 +0100

Newsgroups	gmane.comp.lang.perl.fun
Message-ID	<[email protected]>

On Wed, Mar 14, 2012 at 07:48:35AM -0700, John Douglas Porter wrote:
[ ~~ vs. scalar ]
> 
> So is that the Perl 6 smart match operator? or something else?
> In any case... How does it work here?  It looks like it's functionally
> equivalent to scalar()... but why?

It's twice bitwise not, and bitwise not enforces scalar context.
Think ~(~(foo)).