Re: How to replace multiple values of an attribute

Oliver Dörr <[email protected]>
Newsgroups gmane.comp.lang.perl.modules.ldap
Message-ID <[email protected]>
Hmmm,

that does also not work.  $mesg1->error shows "Protocol error " and 
$mesg1->code = 2

No hint, in LDAP server log

Another idea?
Oliver


Steiner, Ross schrieb:
> Oliver,
>
> I think the following should work (pass a reference to an array, not an array):
>
> my $mesg1=$backendConn->modify($dn,
>                                replace => { $attr, $values }
>                               );
>  
> Regards,
> Ross
>
> -----Original Message-----
> From: Oliver Dörr [mailto:[email protected]] 
> Sent: Monday, April 13, 2009 2:41 PM
> To: [email protected]
> Subject: How to replace multiple values of an attribute
>
> Hi,
>
> I spent my whole afternoon searching for a solution for replacing all values of an attrbute by an array.
>
> So what i got is basicly an reference $values to an array of my new values. I could iterate through the array using foreach my $value (@$values) {...}
>
> The code that works is:
> my $mesg1=$backendConn->modify($dn,
>                                         replace => [$attr, ["Hello", "Test"]]
>                                          );
>
> But i need to be more flexible and tried today a lot of variations of...
> my $mesg1=$backendConn->modify($dn,
>                                         replace => [$attr, @{$values}]
>                                          );
>
> This gave me the error...
> Attribute <one of the values in my array> was not found in the schema definition.
> inside the LDAP Server
>
> $attr is a string that contains the name of the attribut.
>
> Could somebody help me?
> Oliver
>
>
>
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