Re: IKC server with multiple clients....can clients communicate directly after subscribtion

An ikc server is indeed required in the setup, but after looking through the
examples and the ikc-architecture.txt doc I think that would be the only
way...... to have a multiple hub-spoke type setup. It is probably a bit of
overkill in my application but it is something I might look into. I'll post
the solution to this attempt later if I follow through.

On Wed, May 13, 2009 at 1:29 AM, Brandon M. Andrews <
[email protected]> wrote:

> Josh803316 wrote:
>
>>  To Whom may want to Help,
>>
>> I have two IKC clients that publish their states to a IKC server (each one
>> is a separate process).
>> I want to be able to use IKC to make both clients talk with each other
>> once
>> they have published their states.
>>
>> I tried to subscribe from one client to the other  client, but I get this
>> error...
>>  1365: Unknown kernel 'ClientImTryingToConnectTo'
>>
>>
> I'm going to work under the assumption that the middleman server is
> required by your network configuration.
>
>  I'm monitoring my connection process and I see that all of the foreign
>> kernels are connected.......but I have to post back to the server who has
>> to
>> post to the other clients.
>> Is there a way to have direct IKC client communication between multiple
>> clients after the publishing/subscription portion is complete?
>>
>>
> I do not believe that this is possible, looking through the IKC
> documentation (and briefly skimming through the code), however I do not
> pretend to be an expert, so if I'm wrong, someone should correct me! :P
>
> From what I know, you would have to spawn another IKC server (on one of
> your original clients) in order to achieve what you want to do. You could
> spawn the server dynamically using information that the clients pass to each
> other through the server, which wouldn't be particularly difficult to
> implement from what I can tell.
>
> I would write example code, but I'm falling asleep at my keyboard. Sorry!
>
> -Brandon
>