Re: Can't remove a call_out.

Interestingly, having two local variables f1 and f2 in check_timeout
both initialized to do_timeout do compare equal but dont have the same
hash_value. That might be a reason why remove_call_out cannot find them.

arne

On 10/24/14 10:25, Stefan Gluszek wrote:
> Seems like a bug, I can't remove a call_out by function name right after
> scheduling it.
> 
> void test()
> {
>     bool testvar = false;
> 
>     void do_timeout()
>     {
>         testvar = true;
>     };
> 
>     void check_timeout()
>     {
>         mixed a = call_out( do_timeout, 20);
>         werror("a: %O\n", a);
>         werror("check_timeout(): %O\n", remove_call_out( do_timeout ));
>         werror("check_timeout(): %O\n", remove_call_out( a ));
>     };
> 
>     check_timeout();
> }
> 
> int main(){
>     call_out(test, 0);
>     return -1;
> }
> 
> I am able to remove it by the call out id returned from call_out. Also I am
> able to remove the call out if I remove the testvar variable or move it
> into the global scope.
> So this works:
> 
> void test()
> {
> 
>     void do_timeout()
>     {
>        werror("to\n");
>     };
> 
>     void check_timeout()
>     {
>         mixed a = call_out( do_timeout, 20);
>         werror("a: %O\n", a);
>         werror("check_timeout(): %O\n", remove_call_out( do_timeout ));
>         werror("check_timeout(): %O\n", remove_call_out( a ));
>     };
> 
>     check_timeout();
> }
> 
> int main(){
>     call_out(test, 0);
>     return -1;
> }
> 
> 
> Stefan
>