Re: What is shadowing

The external x is not visible because THERE IS ANOTHER x, defined "inside"
a block, notice the second "val x = "

This second x hides the first one, in that block

val x = 0 // external

....  {
    val x = ... // internal to this block, shadows, hides the external x
}


Angel "Java" Lopez
@ajlopez



On Sun, Jun 21, 2015 at 6:09 PM, sebastian_cheung via scala-language <
[email protected]> wrote:

> Following Coursera and lecture example:
>
> Why f is visible from within definition of 'result' and x is not?
>
> Thanks
>
> val x = 0
>
> def f(y: Int) = y + 1
>
> val result = {
>   val x = f(3)  //f is externally defined
>   x * x   // but x is internally defined, shadows the occurrence of the outer x
> } + x
>
>  --
> You received this message because you are subscribed to the Google Groups
> "scala-language" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to [email protected].
> For more options, visit https://groups.google.com/d/optout.
>

-- 
You received this message because you are subscribed to the Google Groups "scala-language" group.
To unsubscribe from this group and stop receiving emails from it, send an email to [email protected].
For more options, visit https://groups.google.com/d/optout.