suppressing compiler output
"Buday, Gergely Istvan" <[email protected]>
| Newsgroups | gmane.comp.lang.sml.smlnj |
|---|---|
| Message-ID | <89AE2DBAB3A9E943A358F9780F266AC30115BB5C@budgw09a.ww300.siemens.net> |
Hi,
I'd like to suppress compiler output. What I have, following smlnj.org
is
sml <<EOF
Control.Print.out := {say=fn _=>(), flush=fn()=>()};
CM.make("sources.cm");
Main.doit();
EOF
in my script (I would like to imitate #!/usr/local/bin/sml) but that
does display some autoloading information:
[library $smlnj/compiler/current.cm is stable]
[library $smlnj/compiler/sparc.cm is stable]
[library $smlnj/viscomp/core.cm is stable]
[...]
Is it possible not to have these without hacking the compiler?
Best Wishes
- Gergely
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