Re: Seeking Endorsement: Boost.int128
Peter Dimov via Boost <[email protected]>
| Newsgroups | gmane.comp.lib.boost.devel |
|---|---|
| Message-ID | <[email protected]> |
Matt Borland wrote: > > > How does this relate to / interact with __(u)int128_t? > > > If __(u)int128_t exists, then all operators between those types and the > boost.int128 types are defined: construction, conversion, add, sub, mul, div, > etc. Same case if you have MSVC's std::_Unsigned128 or std::_Signed128 as > the "builtin" 128-bit type. The alignment of the boost.int128 types is also set > to match the builtin types when they exist. Internally, the boost.int128 types > are a struct of two 64-bit integers regardless of the platform. What do the operations actually do, though? Does adding boost::uint128, when __uint128_t exists, use __uint128_t addition, or does it continue to use the library implementation? Similarly, for mixed mode; what does adding boost::uint128 and __uint128_t do under the hood? (And what is the return type? I assume boost::uint128?) _______________________________________________ Boost mailing list -- [email protected] To unsubscribe send an email to [email protected] https://lists.boost.org/mailman3/lists/boost.lists.boost.org/ Archived at: https://lists.boost.org/archives/list/[email protected]/message/QEUCRBD55HLEU6ZJ7I77XVEBZH7BW2CO/