Re: Making explicit the conversion between unless types

Caio Souza <[email protected]>
Newsgroups gmane.comp.lib.boost.ublas
Message-ID <CABb5rj_baM=mBnSVMHX0FwdCj-O2b2ks3XbXZutGs_8A-671UQ@mail.gmail.com>
Received

Em ter, 28 de jun de 2016 14:04, Riccardo Rossi <[email protected]>
escreveu:

> This is just to be sure my previous email was received
>
> Can anyone acknowledge receipt?
>
> Riccardo
> On 24 Jun 2016 3:49 p.m., "Riccardo Rossi" <[email protected]> wrote:
>
>> Dear all,
>>
>> Right now the following code
>>
>> #include <iostream>
>> #include <iostream>
>> #include <boost/numeric/ublas/matrix.hpp>
>>
>> void f(
>>     const boost::numeric::ublas::bounded_matrix<double,10,1>&
>> should_be_10by1
>>      )
>> {
>> }
>>
>> int main() {
>>     boost::numeric::ublas::bounded_matrix<double,10,1> correct;
>>     boost::numeric::ublas::bounded_matrix<double,1,10> wrong;
>>     f(correct);
>>     f(wrong); //how can this be compiled??? - i expect the type of wrong
>> to be ...wrong for f!!
>> }
>>
>> Does compile, effectively bypassing type safety.
>>
>> Essentially if I use a reference in defining a function it is because I
>> don t want to pass by value.
>> In this case a copy is being done...allowed by the fact that the
>> reference I pass is constant.
>>
>> Couldn't t the conversion be made explicit? That would potentially
>> uncover many bugs...
>>
>> Regards
>> Riccardo
>>
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