Issue with Python 3.12 and Concurrent Threads
jholbrook--- via Boost-users <[email protected]> Wed, 18 Jun 2025 15:19:51 -0000
| Newsgroups | gmane.comp.lib.boost.user |
|---|---|
| Message-ID | <[email protected]> |
Hi, I have a Windows application that has been using Boost Python for many years now, and we are looking to upgrade from Python 3.7 to Python 3.12. This is a C++ application written in Qt5 that uses Boost Python to interface with Python scripts that do some scientific calculations, and the results are displayed in the C++ application. As such, these calculations are by and large done on a concurrent thread so as not to block the UI; however, some quick python functions are run from the main thread.
The problem is that *something* changed in the Python 3.12 upgrade, and I'm not sure what -- but now it crashes when I run Python code from a different thread from the one I called Py_Initialize() on. I've tested up to Python 3.11, and I can Py_Initialize() on the main thread and call Python code from any thread and everything works. But starting in Python 3.12, that's no longer the case. If I initialize Python on the UI thread, I can only run it from that thread. If I initialize it on a concurrent thread, I can only run it on a concurrent thread.
Since I am using Python, Qt5, and Boost Python, I am not 100% sure where the fault lies, but I am posting this here in case anyone has run into this issue. I haven't found any other references to it online. I can post a minimal example project if that would be helpful for debugging. Essentially, this is the meat of my code:
//Initialization Function:
Py_Initialize();
//Boost Python Code:
boost::python::object main = boost::python::import("__main__");
boost::python::object name_space(main.attr("__dict__"));
boost::python::exec_file("testPython.py", name_space, name_space);
double testNumber = boost::python::extract<double>(name_space["testNumber"]);
qDebug() << testNumber; //print(testNumber)
#testPython.py:
import random
testNumber = random.random()
Thanks for any help you can provide.
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