Bug in memccpy
Bugs Reporter <[email protected]>
| Newsgroups | gmane.comp.lib.newlib |
|---|---|
| Message-ID | <CAB_V0MAXh9QOBARo-G3YnxmBS5fk4_70cE33vMppgg4HvNe=8w@mail.gmail.com> |
Hi,
I am writing to report a bug in the memccpy function of newlib.
The bug is in the C implementation of memccpy as located in the
newlib/libc/string/ directory of the newlib repository. The newlib version
was `4.2.0` and the source code was downloaded from the latest release
<https://sourceware.org/pub/newlib/newlib-4.2.0.20211231.tar.gz> on the
official website.
Please find a detailed report below.
memccpy():
As specified in the OpenBSD manpage[0], memccpy should convert the input
argument `c` to `unsigned char` before performing the check. Newlib's fast
implementation of `memccpy` (when the macros `PREFER_SIZE_OVER_SPEED` and
`__OPTIMIZE_SIZE__` are not defined) converts `c` to `signed char` (stored
in endchar) and computes a mask as follows:
```
for (i = 0; i < LITTLEBLOCKSIZE; i++)
mask = (mask << 8) + endchar;
```
This is used to detect `endchar` in one long word and is supposed to
represent a word whose each byte has the same value as `endchar`. But if
the input character lies in the extended ASCII set, then `endchar` is
negative, which leads to an incorrect mask computation.
An example input is:
const char src[] = {1, 2, 3, 4, 5, 192, 6, 7};
char dst[8] = {'A', 'B', 'C', 'D', 'E', 'F', 'G', 'H'};
memccpy(dst, src, 192, 8);
if (dst[7] != 'H') {
printf("BUG!\n");
}
The file that demonstrates the bug can be found here
<https://github.com/compilerai/bug-reports/blob/master/bug_files/newlib_memccpy_bug.c>
.
A patch that applies the necessary fix is available here
<https://github.com/compilerai/bug-reports/blob/master/patch/newlib_memccpy.patch>
.
0: https://man.openbsd.org/memccpy
Thanks,
Jai Arora, Abhishek Rose, Shubhani Gupta, Sorav Bansal
CompilerAI Research Group
IIT Delhi, India