cron

Folks,

I am sure I was sleeping at the wheel regarding this issue, so I need a hit on my neck to the right direction.

I have this little crontab entry:
bml0041:shell_script janos$ cat del_from_sequoia.crontab 
10 * * * * /Volumes/Data/PROJECTS/Sysmon/shell_script/del_from_sequoia.ksh > /dev/null 2>&1

That is I want at 10 minutes after the hour to execute a shell script.

The script is this:

bml0041:shell_script janos$ cat del_from_sequoia.ksh
#!/bin/bash
#
scp [email protected]:/prod2/ase15/sysmon/sysmonlogs/*.log /Volumes/Data/PROJECTS/Sysmon/sysmsa/

ssh [email protected] "find /prod2/ase15/sysmon/sysmonlogs -name '*.log' | xargs rm "

That is first I copy over some files from a remote server to my local machine followed by deleting the files on the remote server.

If I do these two commends on the local machine at the CLI, both works fine.  However executing them via cron is a no go, that is nothing happens.

Now, I see in man crontab, that it wants me to use launchctl and I looked its man page too, but I am not seeing how could I schedule the execution of this script with launchd.

Thanks ahead,

János