Re: How to define a PSD ?

"ClementB [email protected] [Abaqus]" <[email protected]> Wed, 13 Mar 2019 08:04:52 -0700 (MST)
Newsgroups gmane.comp.mathematics.abaqus.user
Message-ID <[email protected]>
Thank you for your help !!

Just to be sure in this case, if i consider the phase spectrum to be equal
to 0 then my real part will be the amplitude of my PSD, is that correct ?

When i run several simulations with and without an imaginary part i get the
same results so i guess it doesn't matter to work with a 0 phase spectrum.
But i don't like the fact that i don't know why i can work with a 0 phase
spectrum. I tried to seek information on that on the web but i didn't find
what i was looking for. Could you explain to me what the imaginary part
represents in terms of physics (except the phase of my PSD) ?

Regards,
Clement



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