Re: Symmetric Functions
"Fabio S." <[email protected]> Thu, 23 Oct 2014 21:42:23 +0200 (CEST)
| Newsgroups | gmane.comp.mathematics.axiom.general |
|---|---|
| Organization | Università di Ferrara |
| Message-ID | <alpine.DEB.2.10.1410232129160.4039@coccobill> |
> On 10/23/2014 01:45 PM, Fabio S. wrote:
>>
>> Consider the following polynomial
>>
>> G := (y-(a*u+b*v))*(y-(a*v+b*u))
>>
>> It is symmetric both in (a,b) and (u,v). I would like to espress it as a
>> polynomial in Z[s,t,u,v,y]
>> where s=a+b and t=ab are the symmetric elementary funcitions on a and b
>>
>> Is it possible in axiom?
>>
>> In other words, I am looking for a command which having G as input, returns
>>
>> y^2 - s*(u+v)*y + (s^2-2*t)u*v + t*(u^2+v^2)
>
> According to
> http://en.wikipedia.org/wiki/Symmetric_polynomial#Elementary_symmetric_polynomials
> the expression (u^2+v^2) doesn't look like an *elementary* symmetric
> polynomial in u and v.
>
Ralf, you are right of course. Maybe I didn't explain well what I looked
for.
I want the result to be expressed in term of the elementary symmetric
polynomials in {a,b}, nothing else: even if what we have is symmetric
also in the {u,v} and hence it can be expressed also in the elementary
symmetric polynomials in {u,v}, I am not interested in this last
expression.
I am interested in trasforming an expression in
Z[a,b][u,v][y]
which is symmetric in a and b in an expression in
Z[s,t][u,v][y]
Anyway, your answer is great (and perfectly satisfactory): thanks a lot!
Fabio