Re: newbie

On Wednesday 02 July 2008, Osman Kemal Kadiroğlu wrote:
> deq:= (x**2 + 1)* D(yx,x,2) + 3*x* D(yx,x) + yx = 0

You need to leave a space between the y and the x in your yx.


deq:= (x**2 + 1)* D(y x,x,2) + 3*x* D(y x,x) + y x = 0

The space is significant: without it, yx is treated as a new symbol that has 
nothing to do with the value y or x - with it, it is treated as the 
application of y on x, y(x), which, by AXIOM convention, means the function 
elt(y,x) since y is not an AXIOM function itself. 



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