Re: A simple question

"Alasdair McAndrew" <[email protected]> writes:

> Sorry about this; I'm a bit out of practice:
> 
> for n in 10..30 repeat output [n, factor(2^n-1)]

for example

(7) -> for n in 10..13 repeat output semicolonSeparate [n::OUTFORM, factor(2^n-1)]
   10;3 11 31
   11;23 89
       2
   12;3 5 7 13
   13;8191
                                                                   Type: Void

or
(8) -> for n in 10..13 repeat output([n, factor(2^n-1)]$List ANY)
   [10,3 11 31]
   [11,23 89]
        2
   [12,3 5 7 13]
   [13,8191]
                                                                   Type: Void

> This gives the first n in factored form which I don't want.  How can I
> obtain the first n in unfactored form?

Just to make sure: what happens is that the interpreter sees the list
constructor [], and tries to find a Type as simple as possible. List FR INT is
simpler than List ANY.

Martin