Taylor Series Reversion error: 'quotient' by 'zero'

Justin Jensen <[email protected]>
Newsgroups gmane.comp.mathematics.maxima.general
Message-ID <CAJW-yNwoWxLLdPcqYBsOvV8sgiRgG1tcyDJS9=oL6oBFfUiZLA@mail.gmail.com>
I'm new to Maxima and Computer Algebra Systems in general. So far Maxima
seems to be exactly what I need right now.

As part of a side project I'm trying to find the inverse of a function. It
has no closed-form function, at least in the general case, so I'm
approximating it with a Taylor series. Note that the series has
coefficients of 0 for the 0th, 1st, and 2nd terms. When I try to do a
reversion of series using the `revert` command, it fails and gives the
error: "'quotient' by 'zero'" (see below). How do I resolve this? Once upon
a time, I used Mathematica to find the inverse of a very similar series and
it worked fine. How do I do this with Maxmia?

(%i1) eq: (2*t-sin(2*t))/%pi;
eq (2*t-sin(2*t))/%pi
(%i9) ser: taylor(eq,t,0,9);
ser
(4*t^3)/(3*%pi)-(4*t^5)/(15*%pi)+(8*t^7)/(315*%pi)-(4*t^9)/(2835*%pi)+...
(%i10) revert(ser,t);
(%o10)
revert(-((4*t^9)/(2835*%pi))+(8*t^7)/(315*%pi)-(4*t^5)/(15*%pi)+(4*t^3)/(3*%pi),t)
(%i11) load("revert")$
(%i61) revert(ser,t);
`quotient' by `zero'

 -- an error. To debug this try: debugmode(true);


Thanks in advance,

-- 
Justin

_______________________________________________
Maxima-discuss mailing list
[email protected]
https://lists.sourceforge.net/lists/listinfo/maxima-discuss
lmpx.com only provides a reader for public news (NNTP) servers. It is not affiliated with the servers or forums shown here and is not responsible for the content of articles, which is written by their respective authors.