add listsum( L, {n=#L}, {s=1} )
"Ruud H.G. van Tol" <[email protected]> Tue, 24 Mar 2026 11:53:26 +0100
| Newsgroups | gmane.comp.mathematics.pari.devel |
|---|---|
| Message-ID | <[email protected]> |
Consider adding listsum( L, {i1 = 1}, {i2 = #L} ).
Much like vecsum( Vec( L[ i1 .. i2 ] ) ) would be,
but without copying any data.
-- Ruud