Re: add listsum( L, {n=#L}, {s=1} )

On 2026-03-26 18:01, Bill Allombert wrote:
 > On Tue, Mar 24, 2026 at 11:53:26AM +0100, Ruud H.G. van Tol wrote:

 >> Consider adding listsum( L, {i1 = 1}, {i2 = #L} ).
 >>
 >> Much like vecsum( Vec( L[ i1 .. i2 ] ) ) would be,
 >> but without copying any data.
 >
 > Rather I just changed vecsum and vecprod to allow t_LIST in commit
 > bb57edd30e55ee386794d80bf7d3556cb9af266d
 >
 > Thanks for the suggestion!

Thanks! What lead me to the suggestion was that I needed to efficiently 
sum a sub-list.
That sub-list was almost the full list, just without a marginal initial 
part,
so in my case I can work around it by subtracting the sum of that 
initial part.

-- Ruud