Re: What’s the equivalent of Mathematica ’s Solve[] Function in Pari/Gp ?
"Thomas D. Dean" <[email protected]>
| Newsgroups | gmane.comp.mathematics.pari.user |
|---|---|
| Message-ID | <[email protected]> |
On 1/12/25 03:14, Bill Allombert wrote: > On Sun, Jan 12, 2025 at 11:46:43AM +0100, Laël Cellier wrote: >> No, >> >> it stops after finding the first solution instead of returning every >> possible values and that’s what I’m needing. > > Given the size of the solution it cannot just try all integers until finding > one that works, it must do something smarter. > >> And even if gcdext was the >> solution, how would I be able to use it since the equation contains a == >> sign ? > > Every equation contains a equal sign by definition. > > Set > RSA260=22112825529529666435281085255026230927612089502470015394413748319128822941402001986512729726569746599085900330031400051170742204560859276357953757185954298838958709229238491006703034124620545784566413664540684214361293017694020846391065875914794251435144458199 > > F=(sqrtint(RSA260)+1)^2 > > You want to solve > > ((25)^2 + x RSA260)/(y) == F > > after multiplying by y one get: > > x*RSA260 -F*y == -(25^2) > > Compute > [X,Y,d]=gcdext(RSA260,F) > we find d=1 so > X*RSA260 + Y*F == 1 > So you just need to multiply by -(25^2) > -(25^2)*X*RSA260 -(25^2)*Y*F == -(25^2) > hence the solution is > > x = -(25^2)*X > y = (25^2)*Y Mathematica indicates there are an infinite number of solutions in the integers by including the constant C[1] in the solution. Maple uses _Z1. Tom Dean