Re: What’s the equivalent of Mathematica ’s Solve[] Function in Pari/Gp ?

"Thomas D. Dean" <[email protected]>
Newsgroups gmane.comp.mathematics.pari.user
Message-ID <[email protected]>
On 1/12/25 03:14, Bill Allombert wrote:
> On Sun, Jan 12, 2025 at 11:46:43AM +0100, Laël Cellier wrote:
>> No,
>>
>> it stops after finding the first solution instead of returning every
>> possible values and that’s what I’m needing.
> 
> Given the size of the solution it cannot just try all integers until finding
> one that works, it must do something smarter.
> 
>> And even if gcdext was the
>> solution, how would I be able to use it since the equation contains a ==
>> sign ?
> 
> Every equation contains a equal sign by definition.
> 
> Set
> RSA260=22112825529529666435281085255026230927612089502470015394413748319128822941402001986512729726569746599085900330031400051170742204560859276357953757185954298838958709229238491006703034124620545784566413664540684214361293017694020846391065875914794251435144458199
> 
> F=(sqrtint(RSA260)+1)^2
> 
> You want to solve
> 
> ((25)^2 + x RSA260)/(y) == F
> 
> after multiplying by y one get:
> 
> x*RSA260 -F*y == -(25^2)
> 
> Compute
> [X,Y,d]=gcdext(RSA260,F)
> we find d=1 so
> X*RSA260 + Y*F == 1
> So you just need to multiply by -(25^2)
> -(25^2)*X*RSA260 -(25^2)*Y*F == -(25^2)
> hence the solution is
> 
> x = -(25^2)*X
> y = (25^2)*Y

Mathematica indicates there are an infinite number of solutions in the 
integers by including the constant C[1] in the solution. Maple uses _Z1.

Tom Dean
lmpx.com only provides a reader for public news (NNTP) servers. It is not affiliated with the servers or forums shown here and is not responsible for the content of articles, which is written by their respective authors.