Re: deciding whether two padic extensions are isomorphic
Fernando Gouvea <[email protected]>
| Newsgroups | gmane.comp.mathematics.pari.user |
|---|---|
| Message-ID | <[email protected]> |
Thank you! I had not really internalized polcompositum; clearly very useful here. Fernando On 1/14/2025 3:32 PM, Bill Allombert wrote: > On Tue, Jan 14, 2025 at 02:42:49PM -0500, Fernando Gouvea wrote: >> In my book on the p-adic numbers, I mention the GP command padicfields, >> which lists out the (finitely many) extensions of a given Q_p of a given >> degree. With the flag 1, it lists the polynomial that generates the >> extension, followed by the ramification index e, the residue degree f, the >> (power of 3 in) the discriminant, and the number of different embeddings in >> an algebraic closure. >> >> gp > padicfields(3,4,1) >> %14 = [[x^4 + 13*x^3 + 64*x^2 + 61*x + 40, 1, 4, 0, 1], >> [x^4 + 2*x^3 + 11*x^2 + 10*x + 4, 2, 2, 2, 1], >> [x^4 + 2*x^3 + 8*x^2 + 13*x + 7, 2, 2, 2, 1], >> [x^4 + 3, 4, 1, 3, 2], >> [x^4 + 6, 4, 1, 3, 2]] >> >> Earlier in the book I had introduced a field F obtained from Q_3 by >> adjoining a cube root of 1 and a square root of 2. That is an extension of >> degree 4 with e=f=2, so it is either the second or the third in this list. >> How might one decide which? In other words, given two polynomials of degree >> 4, is there a way to use GP to decide whether they define the same >> extension? > Yes, but I do not know the best way to do it. > One way which is simple but not very efficient: > > ? P=polcompositum(x^2+x+1,x^2-2)[1] > %32 = x^4-2*x^3-x^2+2*x+7 > ? L=padicfields(3,4,1) > %33 = [[x^4+13*x^3+64*x^2+61*x+40,1,4,0,1],[x^4+2*x^3+11*x^2+10*x+4,2,2,2,1],[x^4+2*x^3+2*x^2+7*x+16,2,2,2,1],[x^4+3,4,1,3,2],[x^4+6,4,1,3,2]] > > ? foreach(L,l,print(l[1],":",[poldegree(f)|p<-polcompositum(l[1],P);f<-factorpadic(p,3,10)[,1]])) > x^4+13*x^3+64*x^2+61*x+40:[8,8] > x^4+2*x^3+11*x^2+10*x+4:[4,4,4,4] > x^4+2*x^3+2*x^2+7*x+16:[8,8] > x^4+3:[8,8] > x^4+6:[8,8] > > So we see the right polynomial is the second one (we find a compositum of degree 4). > > (this relies on the fact that irreducibility over Qp implies the irreducibility over Q). > > Cheers, > Bill. -- ============================================================= Fernando Q. Gouveahttp://www.colby.edu/~fqgouvea Carter Professor of Mathematics Dept. of Mathematics Colby College 5836 Mayflower Hill Waterville, ME 04901 ...she wears a protective crystal under her shirt, "to absorb the energy of her fans' demands." -- Robin Roberts, in "Anne McCaffrey: A Life With Dragons"