Re: 2^[1,3]

Bill Allombert <[email protected]>
Newsgroups gmane.comp.mathematics.pari.user
Message-ID <Z5qYrWrMOjA5t_Bk@seventeen> 
On Wed, Jan 29, 2025 at 03:51:26PM +0100, Bill Allombert wrote:
> On Wed, Jan 29, 2025 at 03:24:02PM +0100, Ruud H.G. van Tol wrote:
> > 
> > On 2025-01-29 14:42, Bill Allombert wrote:
> > > On Wed, Jan 29, 2025 at 02:28:46PM +0100, Ruud H.G. van Tol wrote:
> > 
> > >> ? vecsum(2^[1,3])
> > >> % 10.000000000000000000000000000000000000

I geuss you can do vecsum([2^i|i<-[1,3]])

Cheers,
Bill.
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