Re: question on converting general cubic equations to Weierstrass format

Max Alekseyev <[email protected]>
Newsgroups gmane.comp.mathematics.pari.user
Message-ID <CAJkPp5OrXF_D794m9eXtY8NSPo26WCYk-E4f6mJ++wtF5NZO8Q@mail.gmail.com>
See jac_cubic code at https://sweet.ua.pt/apacetti/cnt-frames.html

Regards,
Max

On Thu, Mar 27, 2025 at 11:41 PM American Citizen <[email protected]>
wrote:

> Recent changes in GP-Pari has unfortunately rendered my code relating to
> cuboids (body/edge/face) non-functional as testing has found out today.
>
> For example, exploring body cuboids, I have the general cubic equation
> (where a,b is found from a Pythagorean ratio r, such as r = 3/4, i.e.
> a=3 and b=4 where a is the numerator of r and b is the denominator of r.
>
> B(a,b) = 0 * X^3 - 4*a*b * X^2*Y + 2*(a^2-b^2) * X*Y^2 + 0 * Y^3 + 0 *
> X^2*Z + 2*(b^2+2*a*b-a^2) * X*Y*Z + 0 * Y^2*Z + 0 * X*Z^2 + 0 * Y*Z^2 +
> 0 * Z^3
>
> I would like to find the Weierstrass normal form for this equation, i.e
> [a1,a2,a3,a4,a6] where y^2 + a1*x*y + a3*y = x^3 + a2*x^2 + a4*x + a6
>
> For the edge and face cuboids I also have
>
> E(a,b) = a*v*(u*u+1) - b*u*(v*v+1) = 0
> F(a,b) = (a^2+b^2)*u*(v^2-1) - 2*a*b*(u^2-1)*v
>
> where a,b are given parameters and u,v are the general variables.
>
> I am seeking the Weierstrass normal form for all 3 equations, B(a,b),
> E(a,b) and F(a,b)
>
> Randall
>
>
>
>
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